Words
Arithmetic
Geometric
Sums
Earlier skills
100

Which is a sequence and which is a series? Explain the difference.


A: 7, 10, 13, …

B: 7 + 10 + 13 + …

A is a sequence: an ordered list of terms.


B is a series: a sum of terms.

100

State the first term and the common difference.


23, 19, 15, 11, …

a = 23


d = 19 − 23

d = −4

100

An item loses 9% of its value each year. What multiplier gives the next year’s value?

r = 1 − 0.09

r = 0.91


The item keeps 91% of its value each year.

100

Find the first term of this infinite geometric series.


s = 30, r =  2/3 

s =  a/(1-r) 

30 =  a/(1-(2/3)) 

30( 1/3 ) = a

a = 10

100

Simplify and write with a rational denominator.


 4/\sqrt2 

 4/\sqrt2  =  4/\sqrt2 * \sqrt2/\sqrt2 

 4/\sqrt2 = (4\sqrt2)/2 

 4/\sqrt2 = 2\sqrt2 

200

What makes a sequence arithmetic or geometric? Identify each pattern.


A: 20, 15, 10, …

B: 2, 6, 18, …

A is arithmetic: the difference stays the same.

d = 15 − 20

d = −5


B is geometric: the ratio stays the same.

r = 6÷2

r = 3

200

Write a general term for this sequence.


−9, −7, −5, −3, …

tₙ = a + (n − 1)d

tₙ = −9 + 2(n − 1)

tₙ = 2n − 11

200

Write a general term for this sequence.


5, −10, 20, −40, …

a = 5

r = −10÷5

r = −2


tₙ = arⁿ⁻¹

tₙ = 5(−2)ⁿ⁻¹

200

Find the sum of the first four terms of this geometric sequence.


a = 2, r = 3

S₄ =  (2(3⁴ − 1))/(3 − 1) 

S₄ =  (2(80))/2 

S₄ = 80


Check: 2 + 6 + 18 + 54 = 80

200

Solve. State both solutions.


(x − 6)(2x + 3) = 0

x − 6 = 0

x = 6


2x + 3 = 0

2x = −3

x = −3/2


300

Write the first four terms of this infinite geometric series. Does it converge or diverge? Explain.


a = 16, r = −1/2

16 − 8 + 4 − 2 + …


It converges because |r| = 1/2 < 1.

300

Find the sum of the first 12 terms.


tₙ = 2n + 5

a = 2(1) + 5

a = 7


t₁₂ = 2(12) + 5

t₁₂ = 29

 Sn = n/2(a+tn) 

S₁₂ =  12/2(7 + 29) 

Sn = 216

300

Find the first term of the geometric sequence.


t₄ = −216, r = −3

tₙ = arⁿ⁻¹

−216 = a(−3)³

−216 = −27a

a = 8

300

Find the first term of this finite geometric series.


Sₙ = −30, r = 0.5, tₙ = −2

Sₙ =  (rtₙ − a)/(r − 1) 

−30 =  [0.5(−2) − a]/(0.5 − 1) 

15 = −1 − a

a = −16

300

Solve and check each possible solution.


 \sqrt(x + 31) = x + 1 

x + 31 = (x + 1)²

x + 31 = x2 + 2x + 1

0 = x² + x − 30

0 = (x + 6)(x − 5)

Candidates: x = −6 and x = 5.

Verify:
x = −6:  \sqrt((-6)+31)  = 5, but x + 1 = −5. Reject.

x = 5:  \sqrt(5+31)  = 6 and x + 1 = 6. Valid.


Only x = 5 is a solution.

400

ODD ONE OUT

A: 3, 6, 9, 12, …

B: 4, 8, 16, 32, …

C: 10, 7, 4, 1, …

Which pattern is different? Explain using common differences or ratios.

B is geometric: r = 2.

A and C are arithmetic.

A has d = 3; C has d = −3.

400

FIX THE PATTERN

6, 10, 14, 19, 22, …

One term is wrong. Repair it, then write a general term formula.

19 should be 18.

The common difference is 4.

tₙ = 6 + 4(n − 1)

tₙ = 4n + 2

400

6, −12, 24, −48, …

A student says the common ratio is 2. Agree or disagree? Give the correct ratio and the next term.

Disagree: the ratio is −2.

r = −12÷6

r = −2

Next term = (−48)(−2)

Next term = 96

400

A mini theatre has 6 rows. The first row has 8 seats, and each row after it has 2 more seats than the last row.

One teammate says there are 48 seats. Another says 78. Who is right? Show the sum.

78 seats is correct.

tₙ = a + (n-1)d

t₆ = 8 + (6 − 1)(2)

t₆ = 18

Sₙ =  n/2(a+tₙ)  

S₆ =  6/2(8 + 18) 

S₆ = 78


400

SPOT THE LOST SOLUTION

A student solves x(x − 5) = 0 by dividing both sides by x. Their only answer is x = 5.

Which solution did they lose? Give both solutions.

They lost x = 0.

x = 0 OR x − 5 = 0

x = 0 OR x = 5


500

TWO TRUTHS AND A LIE

A: A sequence is an ordered list of terms.

B: An arithmetic sequence has a constant difference.

C: Every infinite geometric series with a negative ratio diverges.

Find the lie and fix it.

C is the lie.

An infinite geometric series converges when −1 < r < 1.

For example, r = −1/2 gives a convergent series.

A negative ratio alone does not tell you whether it converges.

500

UNLOCK THE DOOR

The key code is a multiple of 6 between 20 and 50.

How many possible codes are there?
Hint: Start by finding the first multiple of 6 after 20.

There are 5 possible codes.

First = 24; last = 48; d = 6

48 = 24 + (n − 1)6

24 = 6(n − 1)

4 = n − 1

n = 5

Check: 24, 30, 36, 42, 48.

500

PRICE DROP

A $200 game console loses 10% of its value in the first year, then 20% in the second year.

Which value is correct after two years: $140, $144, or $162? 

$144 is correct.

First-year common ratio = 0.90

Second-year ratio = 0.80

t₁  = 200(0.90) = 180

t₂  = 180(0.8)2-1 = 144


500

Your infinite geometric series must have ratio r = 1/2.

What first term makes its sum exactly 32? Write the first four terms as a sum, followed by …

s =  a/(1-r) 

32 =  a/(1-(1/2)) 

a = 16

16 + 8 + 4 + 2 + …

The series converges because |r| < 1.

500

SAME OR DIFFERENT?

A:  6/\sqrt3 

B:  2\sqrt3 

Two teammates say these are different answers. Are they right? Rationalize A to settle it.

They are the same answer.

 6/\sqrt3  =  (6/\sqrt3)(\sqrt3/\sqrt3) 

 6/\sqrt3  =  (6\sqrt3)/3 

 6/\sqrt3  =  2\sqrt3 

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