Systems of Equations
Factoring
Matrices
Exponents
Logs
100

Let's solve your system by substitution.

x+y=7

x+2y=11



x=3 and y=4

100

Factor using GCF(Greatest Common Factor)

A: 16p4 +4p3


4p3(4p + 1)


100

Solve by using Addition: 3x2

[3  6]        [0  -1]  

[-1 -3]   +  [6  0]  =

[-5 -1]       [2  3]

A: 3x2

[3 5]

[5-3]

[-3 2]


100

Laws of Exponents Product Rule:

x3 * x8 =

A:

x11

100

log x(8) =1/3

x=512

200

Use elimination to solve for x and y.

4x  + 2y = 14

5x  + 2y = 16

The solution is (2, 3).

200

Factor Using Difference Of Squares:

A: 36k2 −1


(6k+1)(6k−1)


200

Solve Using Inverse:2x2

[11 -5]

[2  -1]

A:2x2

[1 -5]

[2 -11]

200

Simplify:

x5 * x3 =

A:x8

200

log2(64) = x-4

x=10

300

Solve for x and y.

-x – y = -4

x + y = 2

-x – y  = -4

x + y   =  2

0 = −2

Add the equations to eliminate the

x-term.

Answer

There is no solution.

300

Factor the Trinomial:

A: n2 −n−56


(n + 7)(n − 8)


300

find the determinant of this 2x2:

[-1 1]

[-1 4]

A: -3


300

Solve:

43/2=

A: 8

300

(1/7)^x=7^x+4

x=-2

400

Solve for x and y.

x + y = 2

-x − y = -2

x + y  =  2

-x − y = -2

 0 =   0  

Add the equations to eliminate the

x-term.

Answer

There are an infinite number of solutions.

400

Factor Using the AC Method:

A: 10x2 -3x-1


(5x+1)(2x−1)


400

Solve Using Inverse of Matrices:

 


A:

 

400

Compound Interest: hint:  A = P (1 + r/n)(nt)

You borrowed $59,000 for 2 years at 11% which was compounded annually. What total will you pay back?



A: $72,693.90


400

e^In(2.5)

2.5

500

Use elimination to solve the system.

x – y = −6

x + y = 8

2x = 2

x = 1

Solve for x.

 x + y = 8

1 + y = 8

y = 8 – 1

y = 7

Substitute x = 1 into one of the original equations and solve for y.

x – y = −6

1 – 7 = −6

−6 = −6

The solution is (1, 7).

 

500

Factor by Grouping:

A: 140ab−60a2 +168b−72a


4(5a + 6)(7b − 3a)


500

Use RREF To solve the system:

{3x+4y=11}

{2x-5y=-8} 

HINT:[3 4 11]

        [2 -5 -8]

A: [1 0 1]

    [0 1 2]

500

Compound Interest: hint:  A = P (1 + r/n)(nt)

Your $440 gets 5.8% compounded annually for 8 years. What will your $440. be worth in 8 years?


A: $690.78


500

"Thor spent $12,125 on a credit card with 12.5% annual percentage interest rate compounded continuously. he makes no payments for 2 years. How much does he own then?

A=15568.80

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