Solving Equations
x=-4/5
(7-3i) - (4-9i)
3+6i
5≤ 2x+1 < 13
2≤x<6
[2,6)
Find the center and radius of the circle:
(x+3)2 + (y-4)2 = 12
Center = C(-3,4)
Radius = r = √(12) = 2√(3)
| x+5 | <3
(-8,-2)
x2+x-42=0
x=-7
x=6
Simplify:
i15
-i
(x+4)(x-1)<0
(-4,1)
Find the equation of the line through the point (-7,2) with slope of -3.
y=-3x-19
Solve the following equation:
√(7+x) = √(x2+1)
x = 3,-2
3x2+17x+14=0
x=-14/3
x=-1
Evaluate the radical expression and express the results in the form a +bi:
√(-2) * √(-18)
-6
(x+3)/(x-1) ≥0
(-∞,-3] U (1,∞)
Find the x & y-intercept(s) of the equation:
x2y+16y2 =80
no x-intercept
y-intercept: (0, -√(5)) & (0, √(5))
Solve the following equation:
2x + √(x+6) = 9
3
9x2+24x+16=0
-4/3
Evaluate the product, and write the result in the form a + bi:
(7-3i)(7+3i)
58
|x-4|≥5
[9,∞) OR (-∞,-1]
Find the x & y intercept(s) of the equation:
16x2 + 64y2 + 6xy = 64
X-intercepts: (2,0) & (-2,0)
Y-intercepts: (0,1) & (0,-1)
Find an equation of the circle that satisfies the given conditions: Endpoints of a diameter are P(-1,2) and Q(7,8)
(x-3)2 + (y-5)2 = 25
(1/x-2) + (1/x+2) = 6/5
Find all solutions of the equation. Simplify your answer completely leaving it in radical form:
6x2+12x+7=0
1± (i√(6))/6)
(x-1)2(x+5)>0
(-5,1) U (1,∞)
A pair of points is given: (-6,3) and (4,-2)
a. Find the distance between these points.
b. Find the midpoint of the segment that joins them.
c. Find the slope of the line through these points.
a. 5√(5)
b. (-1,1/2)
c. -1/2
Find an equation of the line that passes through (5,-2) and is perpendicular to the line:
3x - 5y + 15 = 0
y = (-5/3)x + (19/3)