What is equilibrium defined as?
When the rate of the forward reaction equals the rate of the reverse reaction
What are the units of k in the following rate law?
Rate = k [A]5[B]1/2[C]7
M-11.5 s-1
The rate constant for a reaction at 387 K is 4.40×10-3 s-1. The activation energy is 102 kJ/mol. Calculate the rate constant at 492 K.
K2 = 3.82 s-1
How does temperature affect the reaction rate?
Increasing will increase the rate, decreasing will decrease the rate
What is the equilibrium constant (Kc) for the following reaction?
aA + bB <-> cC + dD
Kc = [C]C [D]d/[A]a [B]b
*savannah pull up picture
For the following reaction, determine the orders of A and B and write the rate law.
2A (g) + B (g) -> C (g) + D (g)
A and B: 2nd order, Rate = k[A]2[B]2
For a reaction, the rate constant at 298 K is 4.12×10-3 s-1, and at 318 K, the rate constant is 8.27×10-3 s-1. Calculate the activation energy of the reaction in kJ/mol.
27.4 kJ/mol
How do catalysts affect a reaction?
Positive catalysts lower activation energy and increase the rate, negative catalysts raise activation energy and decrease the rate.
Determine the value of Kc for the following reaction. [A] = 8.9 x 10-4, [B] = 2.5 x 10-4, [C] = 5.6 x 10-5.
3A(g) + 2B(g) ⇌ 1/2C(g)
For a second-order reaction, the rate constant is k = 1.21 x 10⁻³ M⁻¹s⁻¹. If the initial concentration is 0.776 M, calculate the concentration of the substance after 137 seconds.
0.688 M
The rate constant for a reaction at 453 K is 3.5×10-4 s and the activation energy is 97 kJ/mol. Calculate the temperature when the rate constant is 1.2×10-2 s-1.
What values of Kc favor products and what values favor reactants?
Larger than 1, favors products, smaller than 1, favors reactants
The reaction below has a Kp value of 1.70 x 10^4. What is the value of Kc for this reaction at 557 K?
N2(g)+3H2(g)⇌2NH3(g)
Kc = 372
The half-life of a first-order substance is 71 seconds. If its initial concentration is 5.71 x 10^(-4) M, after 19.2 seconds, how much of the substance is left? If the final concentration is 3.92 x 10^(-4) M, how much time has elapsed?
4.73 x 10-4 M, 38.5 seconds
A certain reaction has an activation energy of 68 kJ/mol. The rate constant at 207 K is 3.95 × 10-3 s-1. Calculate the rate constant at 247 K.
K = 2.37 s-1
Exothermic: shifts to the left (reactants)
Endothermic: shifts to the right (products)
Find the equilibrium constant for the overall reaction:
4A(g)+ 2B(g) ⇌ 4D(g) + 2E(g)
Kc = 3.8
The zero-order decomposition of substance B has a half-life of 468 seconds, what is the initial concentration if its rate constant is 8.74 x 10^(-4) M s^(-1)? How much will remain after 307 seconds? How much time has elapsed when the final concentration is 0.112 M?
Initial: 0.818 M, Final: 0.550 M, Time: 808 seconds
The rate constant for a reaction at 273 K is 1.5×10-6 s-1 and at 298 K, it is 3.2×10-3 s-1. Calculate the activation energy for the reaction in kJ/mol. Also, determine the rate constant at 310 K
Ea = 207 kJ/mol, rate constant at 310: 8.17 x 10-2 s-1
What is the relationship between a reaction rate and the value of Kc?
There is none! (sorry it was a trick)