Identify the critical point. f(x)= x2-6x
(3,-9)
Solve 2(e3x-5)-7=9
x=ln(8)+5/3
ln[x/squ(x+2)(1-squ(x))3]
In the long run, f(x)= e1-3x+4 will reach....
a. y=4
b. y= infinity
c. y=-inifinty
d. y=-4
y=4!
For what values is the function increasing? f(x)= (1-x2)/x
the function is never increasing
Derive. f(x)= (e-2x+3)2
-4(e-2x+3)(e-2x)
Solve. log(x)+log(x-11)=log(12)
x=12
y=2x
(1,-2)
Derive. f(x)= (9ex+1)/(3ex+1)
6ex/(3ex+1)2
Derive. y=ln(squ(x+1/3x-4))
1/2[-4/(x+1)(3x-4)]
(1,ln(2))
When is the function concave up? f(x)= 1-x3
when x<0 or (-infinity,0)
Find the equation to the tangent line at the curve of f(x)= e-x^2 at x=3
y= (-6/e9)x+ (19/e9)
The equation of the tangent line to the graph y=xln(x) at x=1
y=x-1
How much interest is earned if $10,000 is initally depostied for 20 years at an interest rate of 8% compounded continuoulsy?
A=10,000e^(0.08)(20)
When is the function concave downward? f(x)= (x+1)/(x-1)
when x>1 or (1, infinity)
Find the inflection poitn for the f(x)= xe-x
x=0,1/2
Derive. y=x2ln(e2x-1)
2xln(e2z-1)+(2x2e2x/e2x-1)
Find the equation of the the tangent line(s) of e-x^2 at its inflection point.
y=-2x+1
y= (-1/e1/4)x+ 3/2e1/4