What is the equation to slope intercept form
Y=mx+b
What is the difference between parallel and perpendicular
Perpendicular line intersect at a 90 degree angle while parallel lines never intersect or touch and have the same slope.
put in slope intercept form : 7+2x=y-x
y=3x+7
Y=3x+1
(0,1),(1,4)
Parallel lines that never intersect or touch.
Parallel Lines
What is the slope of these coordinates (-3,7) (6,-8)
What is -5/3 ?
y=1/2x+2, y = -2x + 3
Parallel, Perpendicular, or Neither
Perpendicular
Put into slope intercept form
m=2 (-3,1)
y -1 = 2(x + 3)
y = 2x + 6 + 1
y = 2x + 7
Y=4x-3
(0,4),(1,1)
A set of coordinates that indicate a point.
Ordered Pair
Find the slope of this linear equation.
2x + 5y = -15
What is -2/5 ?
y=5x-2 , y=1/5x-1
Parallel or Perpendicular or Neither?
Neither :)
Slope would be - 1/5 to be perpendicular to 5
Write an equation passing through the point and parallel to the given line.
(4,7) , y = 3x + 6
First find slope, next use the point slope equation
y - y1 = m(x - x1) to write an equation in slope intercept form.
m = 3, x = 4, y = 7
y - 7 = 3(x - 4)
y -7 = 3x -12
y = 3x - 5
y=-2x-5
(0,-2),(1,-7)
Where the line touches the y axis
y-intercept
What is the slope of these coordinates (3,7) , (4,6)
What is -1?
y=2/3x+2 , y=-3/2x - 4
Parallel or Perpendicular
Perpendicular
Write an equation passing through the point and parallel to the given line.
(-4,-5) , y = 1/2x - 6
First find slope, next use the point slope equation
y - y1 = m(x - x1) to write an equation in slope intercept form.
m = 1/2, y = -5 and x = -4
y + 5 = 1/2(x + 4)
y + 5 = 1/2x + 2
y = 1/2x -3
Graph the linear equation y = 5/2x - 1. Identify the equation of the line graphed.
A. 2x + 5y = -5
B. 2x - 5y = 5
C. 5x + 2y = -2
D. 5x - 2y = 2
What is D?
5x - 2y = 2
-2y = -5x + 2, divide everything by -2 to get:
y = 5/2 x - 1
An equation that graphs a straight line
Linear Equation
Write the equation of a line that runs (-3,2) and (0,2) in slope- intercept form.
2 - 2 = 0 m = 0
0 + 3 3
y - 2 = 0(x - 0)
y = 2
What is y = 2?
Write a linear equation that is perpendicular to y = -1/3x - 4 and passes through (9,4)
m = 3, x1 = 9, y1 = 4
y1 - 4 = 3(x1 - 9)
y1 - 4 = 3x - 27
y1 = 3x - 27 + 4
y1 = 3x - 23
Write an equation passing through the point and PERPENDICULAR to the given line.
(-2, -2); y = -1/5x + 9
m = 5
y + 2 = 5(x + 2)
y + 2 = 5x + 10
y = 5x + 8
4x=y+2
(0,2),(1,6)
y-y1=m(x-x1)
Point slope form