Slope = 4
y-intercept = -7
y = 4x - 7
Slope = -3
Point = (9,2)
y-2=-3(x-9)
(12,8) and (4,3)
5/8
y-2=8(x-3)
y=8x-22
What is the standard form equation?
Ax + By = C
Slope = 1/8
y-intercept = 24
y = 1/8x + 24
Slope = 8
Point = (-6,2)
y-2=8(x+6)
(7,9) and (13,5)
-2/3
y+17=-3(x-1)
y=-3x-14
Write this equation in standard form: y = 3x + 4
3x - y = -4
Line has a slope of -3 and passes through, (0,9)
y = -3x + 9
(9,7) and (4,5)
y - 7 = 2/5 (x - 9) or
y - 5 = 2/5(x - 4)
(-2,7) and (4,7)
0
y-11=1/5(x-5)
y=1/5x+10
Write this equation in standard form: y = -2/3x + 1
2x + 3y = 3
Line has a slope of 0 and passes through; (8,-5)
y = -5
(-2,7) and (3,-5)
y - 7 = -12/5(x + 2) or
y + 5 = -12/5(x - 3)
(0,4) and (0,7)
y+2=1/6(x-3)
y=1/6x-2.5
Write the equation in slope-intercept form: 3x - y = 4
y = 3x - 4
(0,-2) and (3,4)
y = 2x - 2
Identify a point on the line and the slope of the line in the equation y - 6 = 2(x + 4)
m = 2
(-4, 6)
(-9,-7) and (7,-4)
3/16
Write an equation in Point-Slope form that passes through: (-3, 10) and (1, 2)
Then write the equation in Slope-Intercept Form.
y - 2 = -2(x - 1) or y - 10 = -2(x + 3)
and y = -2x + 4
Write the equation in Standard Form that passes through (3, 5) (-2, 10):
x + y = 8