concentration!
solutions jargon
pH/pOH
concepts for your life
100
The formula for calculating molarity
M = n/V
100
a homogenous mixture made up of 2 or more components
solution
100
Calculate the pH of a HCl solution with [H+] = 0.002M.
pH = -log(0.002)=2.70
100
a substance that changes color after coming in contact with an acid or base.
indicator
200
The concentration of a solution containing 4.5 moles of NaNO3 dissolved in 6.0 liters of water
M = n/V = (4.5mol)/(6.0L)
=0.75M
200
a substance's ability to dissolve under a given set of conditions (e.g. temperature & pressure)
solubility
200
What is the [OH-] of a solution with pOH = 12.7?
[OH^-]=10^(-12.7)=2.0*10^(-13)M
200
an acid donates one of these ions when dissolved in solution
H+
300
calculate the number of moles dissolved in 2.1 L of 1.3 M solution.
n = M x V = (1.3 M)(2.1 L) = 2.73 moles
300
this type of intermolecular force is the reason why water is known as the universal solvent
hydrogen bonding
300
A solution has a [H+] concentration of 1.3 x 10-9 M. Classify the solution as acidic, basic, or neutral.
pH = -log(1.3*10^-9)=8.89
basic
300
a solution that contains more solute than predicted at a given temperature/pressure is said to be
supersaturated
400
A student wishes to dilute 100 mL of 2.0 M solution. The desired concentration of the new solution is 0.5 M. What is the volume of the new solution?
M1V1=M2V2;
(100mL*2.0M)/(0.5M)=400mL
400
The solubility of a gas _______ as temperature increases.
decreases
400
Calculate the [OH-] concentration for a solution with pH = 4.
pOH = 14 - 4 = 10
[OH-] = 10-pOH = 1 x 10-10 M
400
name 2 examples of colligative properties
freezing point and boiling point
500
A 3.8 M solution of CuCl2 is diluted to 2 times its original volume. What is the molarity of the diluted solution?
(3.8)/2=1.9M
500
At 20 degrees C 200mL saturated solution of sugar contains this many grams of solute.
400 grams
the graph shows 200 g dissolved in 100 mL at 20 degrees C. Multiply this by 2 to get 400 g.
500
Calculate the pH of a solution with [OH-] = 2.3 x 10-5 M.
pOH = -log(2.3*10^-5)=4.64
pH = 14-4.64=9.36
500
Write a chemical equation for the autoionization of water.
