Standard Form ,Slope Int
Solve and Graph Inequalities
Absolute Value Inequalities
Discribe the Transformation
Discribe Transformation
100
Put into Point-Slope Form Point (7,2) Slope 3
y-2=3(x-7)
100
Find the solution to the following inequality.
-6a>=-36
a<=6
100
Solve and Graph.
abs(x+4)>5
100
f(x) = (x + 2)3 - 6
Move left 2 and down 6
100
The absolute value function translated to the left 7
f(x) = lx + 7l
200
This is the equation 3x + 3y = 15 written in y intercept form.
y = 5 - x
200
When shading the solution below, would you shade to the LEFT or to the RIGHT?
x>=4
to the Right
200
Solving Absolute Value
|6r + 6| = 60
r = -11 or r = 9
{-11,9}
200
f(x) = x2 + 8
move up 8.
200
f(x) = 1/2x3 - 5
vertical compression by 1/2 and down 5.
300
This is y + 10 = -.5x written in standard form
y + .5x = -10
300
Solve the inequality.
x+4<4
x<0
300
Solving Absolute Value
|4k + 7| = -11
No solution
300
g(x) = -(x - 5)2 + 7
Move right 5, reflect over x-axis, move up 7
300
The quadratic function translated down 3
g(x) = x2 - 3
400
This is the equation y = 10x + 50 written in standard form.
-10x + y = 50
400
Solve.
s-10<=1
s<=11
400
Solve.
abs(2w-1)<11
-5<w<6
400
f(x) = (x + 2)3 - 6
Move left 2 and down 6
400
f(x) = lx - 4l
move to the right 4
500
The Standard form of a line through the point (4, 4) and (5, 6)
2x + y = 8
500
What is the solution to the following inequality?
3x-7<2
x<3
500
Solve.
-5abs(4+n)<-15
n> -1 or n< -7
500
f(x) = -3lx - 5l - 6
What is reflection across x-axis, vertical stretch of 3, move right 5 and down 6
500
It is written as f(x) = |x| and a V-shaped Function.
an Absolute Value