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100

5h + 2 + 2h = 23

7h + 2 = 23

7h = 21

h = 3

100

2(x + 5) = 14

2x+ 10 = 14

2x = 4

x = 2

100

2x + 5 = 3x - 1

5 = x - 1

x = 6

100

4x + 9 = 33

4x = 24

x = 6

100

WRITE AN EQUATION & SOLVE:

Julie is 3 years older than her sister. 

Julie is 11 years old.

How old is her sister?

Let n be Julie's sister's age, so

n + 3 = 11

n = 8

Julie's sister is 8 years old.

200

3b + b - 8 = 4

4b - 8 = 4

4b = 12

b = 3

200

5(d - 2) = 40

5d - 10 = 40

5d = 50

d = 10

200

5x + 5 = 7x - 4

5 = 2x - 4

9 = 2x

x = 4.5

200

x + 3x = -8

4x = -8

x = -2

200

The angles in a triangle are given as 3a, 5a and 4a.

What are their sizes?

3a + 5a + 4a = 180

12a = 180

a = 15

So the angle sizes are 450, 750 and 600.

300

3a + 12 - 6a = -9

-3a + 12 = -9

-3a = -21

a = 7

300

7(4 - t) = -84

28 - 7t = -84

-7t = -112

t = 16

300

3(y + 6) = 5y + 12

3y + 18 = 5y + 12

18 = 2y + 12

6 = 2y

y = 3

300

4(y - 2) + y = -13

4y - 8 + y = -13

5y - 8 = -13

5y = -5

y = -1

300

Find the size of these angles.

3y + 20 = 5y - 20

20 = 2y - 20

40 = 2y

y = 20

Angles = 800 each

400

-6 = -3y + 4 + 5y

2y + 4 = -6

2y = -10

y = -5

400

-2(x - 9) = -24

-2x + 18 = -24

-2x = -42

x = 21

400

5(y + 6) = 3(y + 12)

5y + 30 = 3y + 36

2y + 30 = 36

2y = 6

y = 3

400

-6(m + 1) + 18 = 24

-6m - 6 + 18 = 24

-6m + 12 = 24

-6m = 12 

m = -2

400

Theatre tickets for 2 adults and 1 senior citizen cost a total of £31.  A senior citizen ticket costs £5 less than an adult ticket.  Work out the cost of an adult ticket.

Let t be the cost of an adult ticket.  So a senior citizen ticket would be t - 5.

So, 2t + t - 5 = 31

3t - 5 = 31

3t = 36

t = 12, so an adult ticket is £12.

500

78 = 3c + 12 - c + 4

2c + 16 = 78

2c = 62

c = 31

500

-13(4 + 2a) = 208

-52 - 26a = 208

-26a = 260

a = -10

500

6(x - 5) = 3(x - 2)

6x - 30 = 3x - 6

3x - 30 = -6

3x = 24

x = 8

500

7k - 8 + 2(k + 12) = 52

7k - 8 + 2k + 24 = 52

9k + 16 = 52

9k = 36

k = 4

500

When you count up in ones from any integer, you are counting consecutive integers. Using algebra, three consecutive integers are n, n + 1, and n + 2. The sum of three consecutive integers is 48. What are the integers?

n + n + 1 + n + 2 = 48

3n + 3 = 48

n = 15

The integers are 15, 16, and 17.

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