Factoring
Square Roots
Graphing / other means
Quadratic Formula
Features of Quadratics
100
Use the Zero Product Property to solve the following quadratic equation. (x - 7)(x + 2) = 0
x = 7 x = -2
100

Simplify: sqrt(147)


7sqrt(3)

100

Solve the following quadratic equation: x2 + 6x = -8

x = -2 x = -4

100
What is the quadratic formula?

x = -b +- sqrt(b2 - 4ac) /(2a)

100

Find the x-intercepts of f(x)=-x2+8x-15

x = 3, x = 5

200

Solve the following quadratic equation by factoring. x2 - 6x + 5 = 0

x = 5 x = 1

200

Find the sum and product of the following:

7sqrt(2) and 6sqrt(6)

sum: 7sqrt(2) + 6sqrt(6)

product: 84sqrt(3)

200

Solve the following quadratic equation: x2 - 6x = -5

x = 1 x = 5

200

Solve the following quadratic equation by using the quadratic formula: x2 + 6x + 5 = 0

x = -1 x = -5
200

Find the vertex of f(x)=x2-2x

(1,-1)
300

Solve the following quadratic equation by factoring. 3x2+4x+1 = 0 

x = -1/3   x = -1

300

Simplify: sqrt(4 x^4 y^3)

2x^2 y sqrt(y)

300

Solve the following quadratic equation: x2 - 2x - 24 = 0

x = -4 x = 6

300

Solve the following quadratic equation by using the quadratic formula: x2 + 10x + 74 = 0

x = -5 + 7i

x = -5 - 7i

300

Find the axis of symmetry of f(x)=5x2+2x-2

x = -1/5

400

Solve the following quadratic equation by factoring. x2 - 6x - 27 = 0

x = 9 x = -3

400

Solve the following quadratic equation by using square roots: x2 -9 = -8

1 or -1
400

Solve the following quadratic equation: x2 + 10x = -16

x = -2 x = -8

400

Solve the following quadratic equation by using the quadratic formula: 2x2 + 9x + 4 = 0

x = -1/2 x = -4
400

Find the y-intercept: f(x)=-x2-4x

y = 0

500

Solve the following quadratic equation by factoring. 2x2 - 5x - 3 = 0

x = -1/2 x = 3
500

Solve the following quadratic equation by using square roots: 5x2 + 3 = 128

x = 5 x = -5
500

Simplify the radical expression as much as possible:

sqrt(-32) - 2sqrt(8)

4i sqrt(2) - 4sqrt(2)

500

Solve the following quadratic equation by using the quadratic formula: 9x2 - 6x + 2 = 0

x = 1/3 + 1/3 i

x = 1/3 - 1/3 i

500

How many x-intercepts does a quadratic with imaginary solutions have? Explain why.

0. The imaginary solutions tell us we there was a negative under the radical, which means we cannot find 'real' values for the x-intercpets.

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