Solving trinomials when a=1
Solving trinomials when a>1
Solving using the GCF
Square root method
Solving difference of two perfect squares
100

Solve: x2+10x+25=0

x=-5

100

Solve 2x2-7x+6=0

x= 2, 3/2

100

Solve: 3x2-12x=0

x=0, 4

100

Solve the following quadratic equation by using square roots: x2 = 4

x = 2 x = -2

100

Solve: (x+2)(x-2)=0

x= 2, -2


200

Solve: x2-12x+27=0

x=9, 3

200

Solve 9x2+6x+1=0

x=-1/3

200

Solve: 14x2-7x=0

x= 0, 1/2

200

Solve the following quadratic equation by using square roots: x2 = 121

x= +11 or -11

200

Solve: 9-x2=0

x= 3, -3

300

Solve: x2+2x=24

x= -6, 4

300

Solve: 2x2-x-6=0

x=2, -3/2

300

Solve: 2y2=6y

y= 0, 3

300

Solve the following quadratic equation by using square roots: 4x2 = 400

x = 10 x = -10

300

y2=16

y= 4, -4

400

Solve: x2+6=5x

x= 2, 3

400

Solve: 4y2+12y=-9

y=-3/2

400

Solve: p=4p2

p=0, -1/4

400

Solve the following quadratic equation by using square roots: x2 -9 = -8

x= 1 or -1

400

4x2-3=1

x= 1, -1

500

Solve: y2=-7y+18

x=2, 9


500

Solve: 2x2-3=5x

x=3, -1/2

500

102x2-10x=0

x=0, 1/10

500

Solve the following quadratic equation by using square roots: 5x2 + 3 = 128

x = 5 x = -5

500

Solve: 4k2-100=0

x=5, -5


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