Factoring
x^2-10x+21=0
x={3,7}
5x^2-11=234
x=+-7
When can you use this method to solve a quadratic equation?
ALWAYS
x2=-6+7x
{6,1}
9x^2-25=0
x={-5/3,5/3}
When is it best to use the square root method for solving quadratics?
When there is no 'b' term.
-2x^2+3x=4x-15
x={-3,5/2}
(x-2)2-8=-7
3x^2-13x-30=0
x={-5/3,6}
x^2-1=39
x=+-2sqrt10
x^2-9=4x
x={2+-sqrt13}
7x2+4x-8=0
-2+2sq.root(15)/7
-2-2sq.root(15)/7
3x^2=81-x^2
x={-9/2,9/2}
4x^2-39=10
x=+-7/2
3x^2+8x-7=0
x={(-4+-sqrt37)/3}
4x2-81=0
{9/2, -9/2}
2x^2=x+21
x={-3,7/2}
-2x^2+196=0
x=+-7sqrt2
3x^2+x=2x+7
x={(1+-sqrt85)/6}
7x2-26x+9=-6
{5/7, 3}