Solving Radical Equations #1
(3x-5)^1/4+3=4
x = 2
sqrt(5x+6) = x
x=6
2(x - 3)^1/2 + 1 = 7
x = 12
0.5(x + 2)^1/2 = 1
x = 2
(2x-5)^1/3=3
x = 16
sqrt(4x-3)=5
x = 7
(7x -12)^1/2 = x
:x = 4,3
(x + 3)^1/2 = 2
x = 1
NO QUESTION
FREE POINTS Yaaaaay !
sqrt(-3x+10) - sqrt(-7x+38) = 0
x = 7
NO QUESTIONS
FREE POINTS Yaaaaay
ما هو الجذر الخامس لـ 32- ؟
-2
(2x-8)^2/3 = 4
x = 8,0
sqrt(12x-47) - sqrt(2x+23)=0
x = 7
-2(x + 4)^1/2 + 5= -7
x = 32
(2x - 1)^1/2 = x
x = 1,1
(6x-3)^2/3 + 6 = 15
x = 5, -4
sqrt(-9x-14)=0
x = -14/9
(x^2 + 5x + 12)^1/3 = 2
x = -4, -1
(5x^2 + 14x)^1/3 = x
x = 7, -2, 0