(x+5)2
x2+10x+25
x2 + 6x + 9
(x+3)2
Expand (x+2)2 + (3x-2)2
10x2-8x+8
The area of a square is x2+ 6x+ 9. What is the side length of the square?
x+3
(3y - 2)2
9y2 - 12y + 4
4x2 - 12x + 9
(2x - 3)2
Expand 4x2 - 9 - (3x+1)(2x-3)
−2x2+7x−6
A rectangular garden has a length of x+5 and width x−5 What is the area of the garden?
x2 - 25
(2x - 7)(7 - 2x)
-(4x2 - 49)
= -4x2+49
25x2 - 16
(5x + 4)(5x - 4)
Expand (3x - 2)2 - (2x-1)2
5x2 - 8x +3
The area of Square 1 is (x+2)2 and of Square 2 (2x+1)2. What is the area of the difference of S1 - S2 ?
(x+2)2 - (2x+1)2
= -3x2 + 35(2x + 1/5)2
20x2 + 4x + 1/5
(x-2)2 - 1
(x-3)(x-1)
Factorize 4x2 − 9y2 +(2x + 3y)2
(2x+3y)(2x−3y)+(2x + 3y)2
= (2x+3y)[ (2x-3y)+(2x+3y) ]
=(4x)(2x+3y)
The difference between the squares of two consecutive integers is 15. What are the integers?
8 and 7 (or -8 and -7)
7(5/7 x - 2)2
25/7 x2 - 20x +28
(3x - 4)2 - (3x - 4) + 1
(3x - 4)[(3x-4) - 1] + 1
=(3x - 4) (3x - 5) + 1
Factorize x4 - 16
(x2+4)(x+2)(x−2)
The diagonal of a square is 10 units. Find the area of the square using the identity s2 = d2/2 where s is the side length and d is the diagonal.
50 square units
Factorize (3x+4)2 - (2x+1)2
5(x+1)(x+3)