VOCAB
Margin of Error
Calculate/DO Step
State/Plan Steps
Millennial Internet Trivia
100

What is a single value estimate for a population parameter?

Point estimate

100

Which has a larger margin of error: a 99%, 95%, or 90% confidence interval based on the same raw data?

The 99% confidence interval would have the largest margin of error

100

what is the general equation you should ALWAYS write for the first step of the "do" step?

point estimate ± critical value (st error)

100

Do the STATE step only:

The recommended retail price of a brand of designer jeans is $150. The price of the jeans in a sample of 16 retailers is on average $141, with a sample standard deviation of $4. The prices can be assumed to be normally distributed. Construct a 95% confidence interval for the average sale price.

we will estimate μ=the true mean price of designer jeans at 95% confidence 

100

Vegeta from Dragon Ball Z can't believe that the power level of Goku is "over" this value, in this famous early internet meme

What is 9000?

200

What is an interval or range of values used to estimate a population parameter?

Confidence Interval

200

These are the two ways we can shrink a margin of error

What is...

-Increase sample size and

-Decrease confidence level

200

A random sample of 30 households was selected as part of a study on electricity usage, and the number of kilowatt-hours was recorded for each household in the sample for the first quarter of 2026. The average usage was found to be 375kWh with a standard deviation of 81kWh. Create a confidence interval for a 99% confidence level for the mean usage in the first quarter of 2026?

point estimate ± critical value (st error)

x-bar ± t* (sx/sqrt(n))

df=29

375 ± 2.756 (81/sqrt(30))

(334.24, 415.76)

200

Complete the STATE step only:

A Pew Research Center report on gamers and gaming estimated that 79% of U.S. adults play video games on a computer, TV, game console, or portable device such as a cell phone. This estimate was based on a random sample of 1400 U.S. adults. Construct a 95% confidence interval for the proportion of all U.S. adults who play video games.

We will estimate p=the true proportion of US adults who play video games at 95% confidence
200

Name the character in the image

Who is Salad Fingers?

300

C is the success rate (capture rate) of the method that produces the interval.

What is a confidence level

300

What is the z* for an 84% confidence interval for p

1.405

300

An industrial designer wants to determine the average amount of time it takes an adult to assemble an "easy to assemble" toy. A sample of 16 times yielded an average time of 19.92 minutes, with a sample standard deviation of 5.73 minutes. Provide a 95% confidence interval for the mean assembly time (assume all checks are passed).

point estimate ± critical value (st error)

x-bar ± t* (sx/sqrt(n))

df=15

19.92 ± 2.131 (5.73/sqrt(16))

(16.87, 22.97)

300

What are the three conditions we must check?

Random --> generalize to the population

Independent  --> 10% condition

Normal  -->  Large Counts (10/10)/ CLT

300

In a viral World of Warcraft video, this player with what name charged into a high-level battle after being AFK during his raid groups complex planning session

Who is Leeroy Jenkins?

400

When asked to "construct and interpret" a confidence interval, what are the four steps you must follow? :

State, Plan, Do, Conclude (or choose, check, calculate, conclude)

400

What is the critical value for a 90% confidence interval for population mean with a sample size of 9?

t*=1.86

400

A Pew Research Center report on gamers and gaming estimated that 79% of U.S. adults play video games on a computer, TV, game console, or portable device such as a cell phone. This estimate was based on a random sample of 1400 U.S. adults. Construct a 95% confidence interval for the proportion of all U.S. adults who play video games.

point estimate ± critical value (st error)

p-hat ± z*sqrt((p-hat(1-p-hat)/n)

0.79 ± 1.96 sqrt(0.79*0.21/1400)

(0.77,0.81)

400

Complete the PLAN step only:

The recommended retail price of a brand of designer jeans is $150. The price of the jeans in a sample of 16 retailers is on average $141, with a sample standard deviation of $4. The prices can be assumed to be normally distributed. Construct a 95% confidence interval for the average sale price.

1-sample t-interval for  μ

Random: SRS of 16 retailers

Normal: Population is approximately normally distributed, so ~Normal

Independent: 16 is less than 10% of designer jeans retailers

400

"New exciting flavors" of this item start out normal: 

Rasberry. Cranberry. Apples. Cinnamon. Pecan.

Before becoming more absurdist, including: 

Fish, Paperclip, Isreali-Palistinian conflict, Bits of glass, and FIRE!!

What are (Cunningham) Muffins?


500

What is the number of free choices left after a sample statistic is calculated? This is a value you only need for means-type problems

Degrees of freedom

500

We estimate with 95% confidence that between 81% and 87.4% of all adult residents of this city have cell phones.

What was the point estimate?

What was the margin of error?

point estimate=the average of 87.4 and 81:

(87.4+81)/2=84.2


Margin of error=87.4-84.2=3.2

500

A 2016 survey of 1480 randomly selected U.S. adults found that 55% of respondents agreed with the following statement: “Organic produce is better for health than conventionally grown produce."

 Construct a 99% confidence interval for the proportion of all U.S. adults who think that organic produce is better for health than conventionally grown produce

point estimate ± critical value (st error)

p-hat ± z*sqrt((p-hat(1-p-hat)/n)

0.55 ± 1.645 sqrt(0.55*0.45/1480)

(0.53,0.57)

500

Complete the PLAN step only for this problem:

A 2016 survey of 1480 randomly selected U.S. adults found that 55% of respondents agreed with the following statement: “Organic produce is better for health than conventionally grown produce."

 Construct a 99% confidence interval for the proportion of all U.S. adults who think that organic produce is better for health than conventionally grown produce

1-sample z-interval for p

random: SRS of 1480 US adults

Normal: .55*1480=814>10 and .45*1480=666>10 so ~Normal

Independent: 1480 is less than 10% of all US adults

500

This number, also noted by the singer of this song as his "girlfriend's age" and "my IQ" is how high the singer can count "alllll de way to"

Schfifty-five

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