Percentages
What is the formula for percent yield?
(Actual/Theoretical)*100
C3H8 + 5O2 --> 3CO2 + 4H2O
What is the mole ratio of CO2 to C3H8?
3:1
Cl2 + 2 Na --> 2 NaCl
How many grams of NaCl can be produced from 7.5 moles of Cl2?
876.6 g of NaCl
2 K + Br2 --> 2 KBr
How many moles of KBr can be produced from 4.25 grams of K?
0.109 mol KBr
3 Cu2CrO4 + 2 Fe --> Fe2(CrO4)3 + 6 Cu
What is the molar mass of Fe2(CrO4)3?
459.7 g/mol Fe2(CrO4)3
What is the percent composition of BaSO4?
Ba= 58.83%
S= 13.75%
O= 27.42%
C3H8 + 5O2 --> 3CO2 + 4H2O
If 5 moles of C3H8 reacted with excess oxygen gas, how many moles of water would be produced?
20 mol H2O
2 Al + 3 Br2 --> 2 AlBr3
If 2.7 moles of Al reacts with excess Br to form AlBr3, what is the theoretical yield in grams?
720.04 g of AlBr3
2 Al + 3 Br2 --> 2 AlBr3
If 2.7 grams of Br2 reacts with excess Al to form AlBr3, what is the theoretical yield in moles?
0.011 mol AlBr3
2 AlBr3 + 3 Cl2 --> 2 AlCl3 + 3 Br2
How many grams of AlCl3 would be produced from 6.33 grams of Cl2?
7.94 grams AlCl3
What's the empirical formula for a compound with 15.50g of phosphorous, 31.87g of oxygen.
PO4
4 KMnO4 + Sn(SO3)2 --> 2 K2SO3 + Sn(MnO4)4
If 3.2 moles of KMnO4 reacts with 3.00 moles of Sn(SO3)2 to produce K2SO3, what is the limiting reactant?
KMnO4 (1.6 moles of K2SO3)
2 K + Br2 --> 2 KBr
If 3.2 moles of K reacts with 1.2 moles of Br2, what is the theoretical yield of KBr in grams?
285.6 g KBr
Cl2 + 2 Na --> 2 NaCl
If 17.5 g of Cl2 reacts with 27.0 g of Na, how many moles of NaCl will be produced?
0.49 mol NaCl
3 Cu2CrO4 + 2 Fe --> Fe2(CrO4)3 + 6 Cu
If 21 grams of Cu2CrO4 reacts with 17 grams of Fe, how many grams of Cu can be produced?
10.98 g Cu
What's the molecular formula if the empirical formula is SiOBr2 and the molar mass is 611.7g/mol.
Si3O3Br6
__ Cu2CrO4 + __ Fe --> __ Fe2(CrO4)3 + __ Cu
If 17.6 moles of Cu2CrO4 reacts with 18.1 moles of Fe, how many moles of Cu can be produced?
35.2 moles of Cu
__ AlBr3 + __ Cl2 --> __ AlCl3 + __ Br2
If 2.5 moles of AlBr3 reacts with 3.5 moles of Cl2, how many grams of AlCl3 can be produced?
311.10 g AlCl3
__ C3H8 + __ O2 --> __ CO2 + __ H2O
If 95.0 grams of C3H8 reacts with 95.0 grams of O2, how many moles of water will be produced?
2.38 moles of H2O
__ CS2 + __ Cl2 --> __ CCl4 + __ S2Cl2
If 35 grams of CS2 reacts with 72 grams of Cl2 to produce S2Cl2, how many grams of CCl4 can be produced?
576.48 g CCl4
Find the molecular formula from the percent composition and molar mass of the compound.
Hydrogen is 1.58%, nitrogen is 22.22%, and oxygen is 76.19% with a molar mass of 63g/mol.
HNO3
C3H8 + 5O2 --> 3CO2 + 4H2O
If 3.25 moles of C3H8 reacted with 1.05 moles of O2 to produce a certain amount of water, which is the excess reactant and how much excess would there be?
3.04 excess moles of C3H8
2 AlBr3 + 3 Cl2 --> 2 AlCl3 + 3 Br2
If 2.5 moles of AlBr3 reacted with 4.7 moles of Cl2 to produce a certain grams of AlCl3, which is the excess reactant and how many grams of excess would there be?
151.88 g of Cl2
3 Mg + Fe2O3 --> 2 Fe + 3 MgO
If 2.75 grams of Mg reacts with 1.05 grams of Fe2O3 to produce a certain amount (in moles) of MgO, which is the limiting reactant and how much excess reactant will there be?
Fe2O3 is the LR. There is 0.09 moles of excess Mg (ER)
CS2 + 3 Cl2 --> CCl4 + S2Cl2
If 8.5 grams of CS2 reacts with 15.25 grams of Cl2 to produce a certain amount of S2Cl2, which is the excess reactant and how many grams of the excess reactant will you have?
3.02 g of CS2