Mole-Mole Calculations
Mole-Mass Calculations
Mass-Mass Calculations
Percent Yield and Mass-Particles Calculations
Bringing it All Together
100

2C4H10 + 13O2 --> 8CO2 + 10H2O

If 2.75 moles of C4H10 reacts, calculate the number of moles of water that would be produced.

Given - 2.75 moles C4H10

Looking for - moles H2O

Know - 2 moles C4H10: 10 moles H2O

2.75 moles C4H10 x 10 moles H2O/2 moles C4H10 = 13.75 moles H2O

100

3NO2 + H2O --> NO + 2HNO3

If 7.58 grams of NO2 reacts, calculate the number of moles of NO that would be produced.

Given - 7.58g NO2

Looking for - moles NO

Know - 3 moles NO2: 1 mole NO, 46.005g/mol NO2

7.58g NO2 x 1 mole NO2/46.005g NO2 x 1 mole NO/3 moles NO2 = 0.0549 moles NO

100

5C + 2SO2 --> CS2 + 4CO

Given 42 grams of carbon, calculate the mass of SO2 needed for the reaction.

Given - 42g C

Looking for - mass SO2

Know - 5 moles C: 2 moles SO2, 12.011g/mole C, 64.064g/mole SO2

42g C x 1 mole C/12.011g C x 2 moles SO2/5 moles C x 64.064g SO2/1 mole SO2 = 90g SO

100

4Fe + 3O2 --> 2Fe2O3

If 245.75 grams of iron react, and if the actual yield is 315.5g, calculate the theoretical yield of Fe2O3.

Given - 245.75g Fe

Looking for - grams Fe2O3

Know - 4 moles Fe: 2 moles Fe2O3, 55.845g/mole Fe, 159.687g/mole Fe2O3

245.75g Fe x 1 mole Fe/55.845g Fe x 2 moles Fe2O3/4 moles Fe x 159.687g Fe2O3/1 mol Fe2O3 = 351.36g Fe2O3

315.5g (actual yield)/351.36g (theoretical yield) x 100% = 89.79%

100

If you start with 158.6g of ammonium sulfate that has a double replacement reaction with barium nitrate, how many grams of ammonium nitrate are produced?

192.0g NH4NO3

200

2C4H10 + 13O2 --> 8CO2 + 10H2O

If 4.50 moles of oxygen reacts, calculate the number of moles of carbon dioxide that would be produced.

2.77 moles CO2

200

3NO2 + H2O --> NO + 2HNO3

If 4.57 moles of NO2 reacts, calculate the number of grams of water that would be required for the reaction.

27.4g H2O

200

5C + 2SO2 --> CS2 + 4CO

If 25.0 grams of SO2 react, calculate the mass of CO produced.

21.9g CO

200

5C + 2SO2 --> CS2 + 4CO

Calculate the number of particles of carbon disulfide formed if you start with 514.48 grams of carbon.

5.1572 x 1024 particles CS2

200

If you start with 64.67g of C2H6, how many grams of water will be produced in a combustion reaction?

116.2g H2O

300

2C4H10 + 13O2 --> 8CO2 + 10H2O

If 2.45 moles of water are produced, how many moles of oxygen would be needed for the reaction?

3.19 moles O2

300

3NO2 + H2O --> NO + 2HNO3

If 25.0 grams of HNO3 are produced, calculate the number of moles of NO2 needed for the reaction.

0.595 moles NO2

300

5C + 2SO2 --> CS2 + 4CO

If 82 grams of CO are produced, calculate the mass of SO2 needed for the reaction.

94g SO2

300

3NO2 + H2O --> NO + 2HNO3

Calculate the number of molecules of water needed to make 57.5 grams of HNO3.

2.75 x 1023 molecules H2O

300

Hydrogen sulfate is produced in a synthesis reaction between water and sulfur trioxide. If 138.61g of hydrogen sulfate is produced, how much sulfur trioxide did you start with in grams?

113.15g SO3

400

2C4H10 + 13O2 --> 8CO2 + 10H2O

How many moles of C4H10 would be needed to react with 2.25 moles of oxygen?

0.346 moles C4H10

400

3NO2 + H2O --> NO + 2HNO3

If 4.8 moles of NO are produced, calculate the mass of NO2 needed for the reaction.

660g NO2

400

5C + 2SO2 --> CS2 + 4CO

Calculate the mass of carbon needed to react with 175.5 grams of sulfur dioxide.

82.27g C

400

5C + 2SO2 --> CS2 + 4CO

Calculate the number of particles of carbon monoxide formed if you start with 165.52 grams of sulfur dioxide. 

3.1110 x 1024 particles CO

400

If 93.18g of oxygen is produced from the decomposition of water, how many grams of the compound did you start with?

104.9g H2O

500

2C4H10 + 13O2 --> 8CO2 + 10H2O

Calculate the number of moles of water that would be made from 12.75 moles of C4H10.

63.75 moles H2O

500

3NO2 + H2O --> NO + 2HNO3

Calculate the mass of NO2 needed to react with 2.85 moles of water.

393g NO2

500

5C + 2SO2 --> CS2 + 4CO

Calculate the mass of carbon monoxide produced when 38.91 grams of sulfur dioxide reacts.

34.03g CO

500

5C + 2SO2 --> CS2 + 4CO

What is the percent yield if 84 grams of carbon disulfide is produced when 75.8 grams of carbon reacts?

84g (actual yield)/96.1g (theoretical yield) x 100% = 87%

500

If you start with 87.56g of potassium hydrogen phosphate that has a single replacement with nitrogen, how many grams of hydrogen phosphate were produced?

3K2HPO4 + N2 --> 2K3N + 3HPO4

Given - 87.56g K2HPO4

Looking for - grams HPO4

Know - 3 moles K2HPO4: 3 moles HPO4, 174.174g/mol K2HPO4, 95.978g/mol HPO4

Answer: 48.25g HPO4

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