Empiric formula
Stoichiometry
Limiting reactant and % yield
Significant figures
100

In a sample are found 1.33 moles of N (nitrogen) and 2 moles of O (oxygen). what is the empirical formula?

N2O3

100

How many moles of O2 are produced by reacting 12 moles of KClO3

2KClO3--->2KCl+3O2 

18 moles

100

3H2(g)+N2(g)-->2NH3(g),   

3 mol H2 is reacted with 6 mol N2. Which is the limiting reactant?    

H2

100

How many significant figures are in the number 520?

2

200

Analysis of 15 grams of a compound shows that it consists of 6g carbon, 1g hydrogen and 8g oxygen. What is the empirical formula?

CH2O

n(C)=6/12=0.5        /:0.5

n(H)=1/1=1            /:0.5

n(O)=8/16=0.5        /:0.5



200

What mass of CO2 would be produced from combustion of 2 moles ethanol (C2H5OH)? 

C2H5OH + 3O2 --> 2CO2 + 3H2O

4x44=176g CO2

200

160g N2H4 is mixed with 160g N2O4. Which is the limiting reactant?    

2N2H4(l)+N2O4(l)-->3N2(g)+4H2O(l)     

N2O4

200

How many significant figures are in number 0.00320

3

300

What is the molecular formula of a compound that consists of only carbon and hydrogen in a ratio of 1:1, and has a molar mass of 78 g/mol?

78/(1+12)=6

C6H6

300

How much CO2 (in mass) would be produced from combustion of 11.5g ethanol (C2H5OH)? 

C2H5OH + 3O2 --> 2CO2 + 3H2O

22g of CO2



300

Fe2O3(s)+3CO(g)-->2Fe(g)+3CO2          

224g of CO is available to react with 400g Fe2O3. How much iron is produced?

279g Fe

300

What is the sum of 3.33+10.666

14.00

400

The empirical formula consists of elements X and Y. Ar(X)=20  Ar(Y)=15. The sample consists of 40% element X. what is the empirical formula?

XY2

n(X)=40/20=2    /:2

n(Y)=60/15=4     /:2


400

4 balloons with a the same volume contain 0.05 mole of gas: Ar, He, H2 and C3H8. Which one is the heaviest?

C3H8

400

In the reaction 2NH3+3CuO-->N2+3Cu+3H2O, 34g NH3 reacted with 340g CuO. 152g of copper were produced. What is the %yield of the reaction?

80%

400

what is the area of a rectangle that its width is 5.55 cm and its length is 1.0 cm?

5.6 cm2

500

A 0.30 g sample of a compound containing carbon, hydrogen and oxygen undergoes complete combustion to produce 0.66 g of CO2 and 0.36 g of H2O. Determine the empirical formula of the compound.

C3H8O

500

3H2(g)+N2(g)-->2NH3(g)   

60cm3 of H2 reacted with 20cm3 of N2. What volume of NH3 was produced?

40cm3 NH3(g)

500

2NH3+3CuO-->N2+3Cu+3H2O

34g NH3 reacted with 340g CuO. Under different conditions, the %yield of the reaction is 90%. How much copper would be produced?

171g Cu

500

Density is calculating by division of a mass/volume. A solvent of mass 5.00 g has a volume of 2.2 cm3. What is the density of the solvent?

2.3 g/cm3

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