Balance the equations
Moles pt. 1
Moles pt. 2
Limiting reactant and Percent yield
Excess reactant
100
Balance the following chemical equation.
CO + O2 
CO2
2 CO + O2 2 CO2
100
How many CaSO4 in kg is required for producing 1 mole of Na2SO4? Assume NaCl in excess.
a) 136 kg
b) 156 kg
c) 176 kg
d) 196 kg
A. 136 kg
100
Ca(OH)2 + 2 HCl 2 H2O + CaCl2
How many moles of Ca(OH)2 are required to react with 6.4 moles of HCl
3.2 mol Ca(OH)2
100
NH3 + O2 NO + H2O. In an experiment, 3.25 g of NH3 are allowed to react with 3.50 g of O2.
Which reactant is the limiting reactant?
O2
100
A reaction container holds 5.77 g of P4and 5.77 g of O2.The following reaction occurs: P4 + O2 P4O6. If enough oxygen is available then the P4O6 reacts further: P4O6 + O2 P4O10.
What mass of excess reactant is left in the reaction container?
5.76 g P4O6 remains
200
Balance the following chemical equation.
KNO3 KNO2 + O2
2 KNO3 2 KNO2 + O2
200
How many kg of Na2SO4 will be produced using 80 kg of NaCl? Assume CaSO4 in excess.
a) 122 kg
b) 142 kg
c) 162 kg
d) 182 kg
B. 142 kg
200
Ca(OH)2 + 2 HCl 2 H2O + CaCl2
How many moles of Ca(OH)2 are required to produce 12 moles of H2O?
6.0 mol Ca(OH)2
200
If 4.95 g of ethylene (C2H4) are combusted with 3.25 g of oxygen.
What is the limiting reactant?
O2
200
Take the reaction: NH3 + O2 NO + H2O. In an experiment, 3.25 g of NH3 are allowed to react with 3.50 g of O2.
How much of the excess reactant remains after the reaction?
1.76 g NH3 remains
300
Balance the following chemical equation.
O3 O2
2 O3 3 O2
300
How many moles of CaCl2 will be produced using 300 kg of CaSO4? Assume NaCl in excess.
a) 2.2 kg
b) 4.2 kg
c) 6.2 kg
d) 8.2 kg
A. 2.2 kg
300
Ca(OH)2 + 2 HCl 2 H2O + CaCl2
How many moles of HCl are required to produce 3.5 moles of H2O?
3.5 mol HCl
300
A reaction container holds 5.77 g of P4and 5.77 g of O2.The following reaction occurs: P4 + O2 P4O6. If enough oxygen is available then the P4O6 reacts further: P4O6 + O2 P4O10.
What is the limiting reactant for the formation of P4O10?
O2
300
For the given reaction
C5H12 + 8 O2 → 5 CO2 + 6 H2O
If the reactants C5H12 & O2 are having 2 moles an 8 moles of initial feed respectively.
1. Which is the excess reactant in the reaction?
a) C5H12
b) O2
c) CO2
d) H2O
A. C5H12
400
Balance the following chemical equation.
NH4NO3 N2O + H2O
NH4NO3 N2O + 2H2O
400
How many pounds of NaCl required producing 2.5 pound moles of Na2SO4? Assume CaSO4 in excess.
a) 200
b) 400
c) 90800
d) 181600
A. 200
400
2 C2H2 + 5 O2 4 CO2 + 2 H2O
How many moles of O2 are required to produce 8.2 moles of H2O?
21 mol O2
400
Consider the reaction of C6H6 + Br2 C6H5Br + HBr
If the actual yield of C6H5Br is 63.6 g, what is the percent yield?
88.8%
400
What is the excess reactant for Al2O3 produced from 5.0 g of Al and 5.0 g of O2.
10.63g Al2O3
500
Balance the following chemical equation.
CH3NH2 + O2 CO2 + H2O + N2
4 CH3NH2+ 9 OO2 4 CO2 + 10 H2O+ 2 N2
500
1/A pound moles of CaSO4 are used to produce 222 kg of CaCl2. What is the value of A? Assume NaCl in excess.
a) 127
b) 227
c) 327
d) 427
B. 227
500
2 C2H2 + 5 O2 4 CO2 + 2 H2O
How many moles of H2O are produced when 10.5 moles of O2 react?
4.20 mol H2O
500
Use the following reaction: C4H9OH + NaBr + H2SO4 C4H9Br + NaHSO4 + H2O If 15.0 g of C4H9OH react with 22.4 g of NaBr and 32.7 g of H2SO4 to yield 17.1 g of C4H9Br, what is the percent yield of this reaction?
61.6%
500
What is the excess reactant of 54.0 grams of Aluminum react with 44.8 L of oxygen gas (O2).
136.4g Al2O3