PEMDAS
Algebraic equations
Translating Algebraic expressions
Percentages
Statistics
100

Solve: 3 + 5 × 2

13

100

Write an equation for: “The sum of a number and 7 is 15." 

x+7=15

100

Write an algebraic expression for:
“The sum of a number and 4.”

x+4

100

What is 10% of 70?

0.10 × 70 = 7

100

What five values are needed to make a box and whisker plot?

Minimum

Q1

Median (q2)

Q3

Maximum 

200

(4 + 6) × 3

30

200

Simplify:3x+5+2x+7

5x+12

200

Write an algebraic expression for:
“5 more than twice a number.”

2x+5

200

What is 30% of 90?

0.30 × 90 = 27

200

Order the numbers and find the median:
7, 10, 4, 9, 12

Ordered: 4, 7, 9, 10, 12 → Median = 9

300

8 + (12 ÷ 4) × 5

23

300

Simplify: 4(2x + 3)

8x + 12

300

Write an algebraic expression for:
“The difference between a number and 7, multiplied by 3."

3(x-7)

300

12 is 40% of what number?

0.40( x) = 12
x = 12 ÷ 0.40 = 30

300

Data: 3, 6, 9, 12, 15, 18, 21
Find the five-number summary.

Answer:
Min = 3, Q1 = 6, Median = 12, Q3 = 18, Max = 21

400

(7 + 3) × (15 ÷ 5) − 4

26


400

Simplify: 2(3x + 4) + 5x

6x + 8 + 5x = 11x + 8

400

Write an algebraic expression for:
“Four times the sum of a number and 6.”

4(x+6)

400

What percent of 64 is 16?

(x) 64 = 16
x = 16 ÷ 64 = 0.25 = 25%

400

Use the five-number summary below to find the IQR:
Q1 = 22, Q3 = 36

IQR = 36 − 22 = 14

500

20 ÷ (2 × 2) + 3²

14

500

Write and simplify an equation for: “Three times the sum of a number and 5 equals 21.”

Equation: 3(x + 5) = 21
Simplify: 3x + 15 = 21

500

Write an algebraic expression for:
“The product of 3 and the difference of a number and 8, decreased by 5.”

3(x-8)-5

500

 A student got 72 questions right on a test, which was 90% of the total. How many questions were on the test?

0.90 (x) = 72
x = 72 ÷ 0.90 = 80

500

A dataset has these five numbers: Minimum = 6, Q1 = 14, Median = 20, Q3 = 27, Maximum = 38.
What is the interquartile range, and what is the total range of the data?

  • Interquartile Range (IQR) = Q3 − Q1 = 27 − 14 = 13

  • Range = Maximum − Minimum = 38 − 6 = 32

M
e
n
u