Graphing #1
Solve by graphing. y=3x-2 y=-3x+4
(1,1)
Solve by graphing. y=7/2x-3 y=1/2x+3
(2,4)
Solve by substitution. y=6x y=x-5
(-1,-6)
Solve by substitution. y=-2x y=x-3
(1,-2)
Rock and Bowl charges $2.75 per game plus $3 for shoe rental. Super Bowling charges $2.25 per game and $3.50 for shoe rental. What is the cost for each after 3 games?
For 3 games Rock and Bowl would charge $11.25
Super Bowling would charge $10.25
Solve by graphing. y=3x+4 y=-3x-2
(-1,1)
Solve by graphing. y=1/3x+2 3y=x+6
Infinite Solutions
Solve by substitution. y=7x+17 y=-3x-3
(-2,3)
Solve by substitution. y=-8 -2x+4y=-22
(-5,-8)
No solutions
Solve by graphing. y=-x + 4 6x-3=y
(1,3)
Solve by graphing. y=-x + 3 5y=-5x - 10
No Solution
Solve by substitution. y=0 -x+2y=-7
(7,0)
Solve by substitution. y=3x+22 -5x-7y=-24
(-5,7)
DOUBLE JEOPARDY.... Question is worth 600 points.
Malory is putting money in two savings accounts. Account A started with $150 and Account B started with $300. Malory deposits $16 in Account A and $12 in Account B each month. In how many months will Account A have a balance at least as great as Account B? What will that balance be?
About 37 months and $750
Solve by graphing. 8x+3y=12 y=-2/3x - 2
(3,-4)
Solve by graphing. 5x-3y=12 y=-2/3x + 3
(3,1)
Solve by substitution. y=8x+4 3x-2y=5
(-1,-4)
Solve by substitution. y=-3x + 6 -3x-8y=-6
(2,0)
A boat travels at a rate of 18 kilometers per hour from its port. A second boat is 34 kilometers behind the first boat when it starts traveling in the same direction at a rate of 22 kilometers per hour to the same port. Let d represent the distance the boats are from the port in kilometers and t represent the amount of time in hours. The system of equations ⎧ ⎨ ⎩ d = 18t + 34 d = 22t can be used to represent this situation. How many hours will it take for the second boat to catch up to the first boat? How far will the boats be from their port?
8.5 hours and they will be 187 km from port.
Solve by graphing. -2y=-7x+8 -4+2y=x
(2,3)
Solve by graphing. -y+2=2x -3y-x=9
(3,-4)
Solve by substitution. 5x+y=1 6x-4y=22
(1,-4)
Solve by substitution. 4x-6y=20 x+2y=-2
(2,-2)
The length of a rectangular room is 5 feet more than its width. The perimeter of the room is 66 feet. Let L represent the length of the room and W represent the width in feet. The system of equations ⎧ ⎨ ⎩ L = W + 5 66 = 2L + 2W can be used to represent this situation. What are the room’s dimensions?
Width of 14 feet and length of 19 feet.