Factoring
Factor the following by GCF:
12x+30
6(2x+5)
Solve
x^2-11x+24=0
x=8 or x=3
Simplify:
sqrt-18
3isqrt2
sqrt90
3sqrt10
How many real solutions does the quadratic have?
-x^2-6x-9=0
one real solution
Factor the following by GCF:
-40x^4-16x^2
-8x^2(5x^2+2)
Solve
x^2+2x-76=4
x=8
x=-10
(-10+4i)+(-4-9i)
-14-5i
sqrt120
2sqrt30
How many real solutions does the quadratic have?
-4x^2-4x=6
none! it has 2 imaginary solutions
Factor the following:
x^2+9x+20
(x+4)(x+5)
Solve
3x^2-10x+7=0
x=7/3
x=1
(-5-6i)-(10+i)
-15-7i
sqrt75x^3
5xsqrt3x
Find the value of c that completes the square
x^2+40x+c
c=400
Factor:
2x^2-7x+5
(2x-5)(x-1)
Solve:
6x^2+x-15=0
x=3/2
x=-5/3
(-5+3i)(9-7i)
-24+62i
Solve using square roots
(x-2)^2=9
x=5
x=-1
An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height s at time t seconds after launch is
s(t)=-4.9t^2+19.6t+58.8
find the maximum height
The maximum height of the object is 78.4 m
Factor & Solve :
3x^2+30x+15
-5+-2sqrt(5)
Solve
9x^2+12x+1=-3
x=-2/3
Divide
(3-2i)/(2+i)
(4-7i)/5
Solve using square roots
(3x^2)/2+1=10
A ball is launched upward at 20 meters per second (m/s) from a 60 meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = -16t2 + 20t + 60, where s is in meters. How long before the object hits the ground after launch?
you can round your square root to the nearest hundredths place (2 decimal places)
2.66 seconds