Expansion
3(x+5) + x(x+5)
(x+5)(3+x)
Sin
Cos
Tan
Cos=Adj/Hyp
Tan=Opp/Adj
3(x-2) + 4x(x+1)
4x^2+7x-6
9x^2-16
(3x+4)(3x-4)
a=13
b=8
Hypotenuse=7
Opposite=5
Adjacent=3
Cos=3/7
Tan=3/5
a=15
c=17
3x^2-27
3(x+3)(x-3)
a=3^2
b=SQR(2)^2
a=SQR(5)^2
c=SQR(7)^2