f(x)= (9-x2)/(x2-2x-3)
domain:
x!=3 x<!=-1
-(3+x)/(x+1)
(3y-1+z-1)/(y-2z-2)
yz(3z+y)
5/(a-3)=-8/(a-6)
a=54/13
sqrt(54w7z14)
3w3z7sqrt(6w)
(sqrt(5)-3)(2sqrt(5)+7)
-11+sqrt(5)
(6x+6)/(2x+4)*(x+2)/(6x2-6)
1/(2(x-1))
(4y/x2)/(3z/5xy)
(20y2)/(3xz)
5/(3x+6)=1/(x2-4)
x=13/5
sqrt(45w5z8)
3w2z4sqrt(5w)
(5sqrt(2)-3)(5sqrt(2)+3)
41
(x+3)/9x2 -: (x2+6x+9)/5x4
5x2/9(x+3)
(6x3+10x2-13x+8)/(3x-1)
2x2+4x-3+ 5/(3x-1)
(x2+1)/(2x2-7x-15)-2/(x-5)=5/(2x+3)
x=4
(8x6y-12)-2/3
y8/4x4
root(3)(2x/50x4y)
(root(3)(5y2))/5xy
7/(y2+5y+4) + 3/(y2+y)
(2(5y+6))/(y(y+1)(y+4))
(2x-1+y-1)/(x-1y-1)
2y+x
A swimming pool can be filled in 8 hours if water enters through a pipe alone, or 20 hours if water enters through a hose alone. If water is entering through both a pipe and a hose, how long will it take to fill the pool?
It will take about 5.71 hours to fill the pool with both the pipe and the hose.
((y-5/6z3/16)4)/z1/20
z7/10/y10/3
root(3)(3x/6x4y2)
(root(3)(4y))/2y
x/(5x2-10x) - (x-8)/(x-2)
(-(5x+39))/(5(x-2))
(8w3-4w2-10w+3)-:(2w-1)
4w2-5+ (-2)/(2w-1)
Samuel can wax his car three times as fast as Daniel. When they work together, they can wax the car in 2 hours. How long would it take Daniel, working alone, to wax the car?
It would take Samuel about 2.67 hours to wax the car by himself. It would take Daniel 8 hours.
(-b1/2b3/4)/b-5/2
-b15/4
(sqrt(x5y11))/sqrt(xy)
x2y5