Approximating and Computing Area and Volume
The Definite Integral
The Fundamental Theorem of Calculus
Substitutions
Random
100

R(8) (right endpoint approximation with n=8), f(x)= 7-x, [3,5]

 R(8)=5.75

100

Calculate the integral: ∫(0,4)  x2dx

64/3

100

Use FTC to find the area under f(x)=x2 on [0,1]

1/3 square units

100

Write the integral in terms of u and du. Then evaluate: ∫(x-7)3dx


∫u3du=1/4(x-7)4+C



100

Evaluate the integral: ∫(6x3-9x3+4x)dx

 3/2x4-3x3+2x2+C

200

R(6) (right endpoint approximation with n=6), f(x)= 2x2-x+2, [1,4]

 R(6)=47.5

200

Calculate the integral of: ∫(0,3) (3t+4)dt

 51/2

200

Find the derivative of the function g(x)=∫(0,x)  √{1+t2} dt 

√{1+x2}

200

∫ cos2 θ sin θdθ  


 − 1/3 cos3 θ+C

200

Calculate the integral: ∫(2x3-1)2dx

 3/2x4-3x3+2x2+C

300

L(5) (left endpoint approximation with n=5), f(x)= x-1, [1,2]

L(5)≈ 0.745635

300

Calculate the integral of: ∫(-3,0) (2x-5)dx

 -24

300

Evaluate using FTC: ∫(-2,0) (3x-2ex)dx

2e-2-8

300

Use the Change of Variables Formula to evaluate the definite integral: ∫(-1,2) √(5x+6)dx 


42/5

300

The demand for a product, in dollars, is p=1200-0.2x-0.0001x2. Find the consumer surplus when the sales level is 500.

$33,333.33

400

Set up the integral (but do not compute it) to find the volume of the solid of revolution generated by revolving the region in the first quadrant bounded by y=x4 and y = 1 about the y-axis

V =  ∫(1,0) π( √ y) dy

400

Calculate the integral ∫(0,0.5) x cos πxdx

(π-2)/2π2

400

Evaluate the integral using FTC: ∫(1,4) (1/t2)dt

3/4

400

∫ x √ (4 − x)dx

− 8/3 (4 − x)3/2 + 2/5 (4 − x)5/2 + C

400

A chemical flows into a storage tank at a rate of 180+3t liters per minute, where 0≤t≤60. Find the amount of the chemical that flows into the tank during the first 20 minutes.

4,200 liters of chemical flow into the tank each minute.

500

M(6) (midpoint approximation), f(x)=lnx, [1,2]

M(6)≈ 0.386871

500

Calculate the integral ∫(1,5) ln(R)/R2 dR

4/5 − 1/5 ln 5

500

Calculate the integral of: ∫(-a,1) (x2+x)dx

1/3a3-1/2a2+5/6

500

∫ √(9-x2) /x2 dx

- √(9-x2) /x-arcsin(x/3)+C

500

A particle is moving along a line so that its velocity is v(t0)=t3-10t2+29t-20 ft/sec at time t. What is the displacement of the particle on the time interval 1≤t≤5?

32/3 ft

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