Molar Mass
Simple Mole
Multistep Mole
EF and MF
Percent Comp.
100

What units that you measure molar mass in?

grams (g)

100

1 mole of molecules/atoms/formula units is equal to ____ and is called _______ ________

6.02*1023, Avogadro's number

100

How many molecules is 36.04g H2O?

1.24*1024 molecules H2O

100

Define Empirical Formula

is the simplest/lowest whole-number ratio of the atoms in a compound.

100

What is the percent composition of NaCl?

39.34% Na

60.66% Cl

200

NaCl

57.44g

200

How many moles in 2.0g of He

0.5 mol

200

how many grams is 120L of CO2?

235.77g CO2

200

If you're given percent composition, what is the first step to finding empirical formula?

First, assume you have exactly 100 grams of the sample and convert the percents to grams.

200

What is the percent composition of CaSO4?

Ca: 29.44%

S: 23.55%

O: 47.01%

300

Al(NO3)3

212.98g

300

How many grams in 1.5 moles of CH4?

24.075g or 24.08g CH4

300

How many molecules are in 10.4L of NO? 

2.80*1023 molecules NO

300

What is the empirical formula for a compound containing 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen?

CH5N

300

What is the percent composition of potassium permanganate? 

K: 24.74%

Mn: 34.76%

O: 40.50%

400

Vanadium (V) oxide

181.88g

400

How many molecules are in 3.75 moles of water? 

2.26*1024 molecules of water

400

how many grams are in 450mL of CO?

0.56g CO

400

What is the empirical formula of a compound containing 47.37% carbon, 10.59% hydrogen, and 42.04% oxygen?

C3H8O2

400

Percent Composition for the oxygen in calcium arsenate

O: 32.15%

500

Manganese (VII) arsenate

1137.26g

500

how many moles is 0.05L of helium gas at STP?

0.0022 moles He

500

How many atoms are in 875 mg of hydrogen gas?

5.22*1023 molecules of H2

500

An unknown compound is found to contain 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen with a molecular mass of 60.0 g/mol. What is the molecular formula of the unknown compound?



C2H4O2

500

what is the percent composition of glucose? 

C: 40.00%

H: 6.71%

O:53.29%

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