Tonicity
Water potential
Solute potential
BONUS QUESTION
100

Tonicity is defined as:

The ability of an extracellular solution to ?? or ?? water

Gain or Lose

100

What are the unit(s) for solute potential?

Megapascals (MPa) and Bars

100

What unit must temperature be in when substituting numbers into the equation to calculate for solute potential?

Kelvin

200

What are the three types of solutions cells can be in?

Isotonic, Hypotonic, or Hypertonic

200

What does water potential indicate?

The direction of the flow of water

200

What unit(s) are used for solute potential?


MPa and or bars

300

Tonicity depends on the concentration of what that cannot pass through the membrane?

Solutes

300

What is the solute potential of pure water? 

Including  units

0 MPa

300

What does the variable i stand for in the equation for solute potential?

Ionization Constant

400

Cells immersed in an isotonic solution have what net movement of water?

A net movement of 0. No net movement is also acceptable.

400

What is the conversion factor from MPa to bars?

1 MPa = x bars

 

10 Bars

400

What is the ionization constant if no ions are formed?

The ionization constant is 1

500

In a hypotonic environment, what will happen to plant cells and what will happen to animal cells? 

Animal cells with swell and lyse

Plant cells will work optimally

500

What is the relationship between an increase in solutes to the binding of free water? 

How does it impact water potential?

a) An increase in solutes incites binding to more free water

b) Water potential is decreased or reduced

500

What are the values for the two Pressure Constants for the following units:

 liter bars/mol-K

liter MPa/mol-K

0.0831 liter bars/mol-K

0.00831 liter MPa/mol-K

500

YOU MAKE TAKE OUT YOUR CALCULATOR FOR THIS QUESTION, BUT NOT YOUR PHONES.

In a lab, a 0.6M sucrose solution is left on a countertop, subject to the open air. Calculate the solute potential at 37 degrees celsius. Round to the hundredths place if necessary. Leave your final answer in bars. 

Solute potential = -iCRT

Solute potential= -(1)(0.6)(0.0831)(310)= -15.4566

Rounded final answer: -15.46 bars 

(Unit must be included)

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