(x+5)(x-1)=0
x= -5
x=1
Solve the equation by completing the square.
p2+14p-38=0
-7 +/- Square root of 87
Solve each equation by taking square roots.
k2=16
k= 4, -4
Find the discriminant of each quadratic equation then state the number of real and imaginary solutions.
6p2-2p-3=0
Discriminant: 76
2 real solutions
Solve using the quadratic formula:
m2-5m-14=0
m= 7
m= -2
(2m+3)(4m+3)=0
m= -3/2
m= -3/4
Write in vertex form and find the vertex using completing the square:
y=a2+14a-51
y= (a+7)2 - 100
VERTEX (-7, -100)
Solve each equation by taking square roots.
2n2=-144
no solution! Can't take the square root of a negative!
Find the discriminant of each quadratic equation then state the number of real and imaginary solutions.
-2x2-x-1=0
Discriminant: -7
2 imaginary solutions
Use the quadratic formula to solve the equation:
b2-4b+4 =0
b= 2
n2+7n+10=0
(n+5)(n+2) so...
n= -5
n= -2
Solve the equation by completing the square.
x2-12x+11=0
x=11
x=1
Solve each equation by taking square roots.
m2+7=88
m= 9, -9
Find the discriminant of each quadratic equation then state the number of real and imaginary solutions.
-2x2-8x-8=0
Discriminant: 0
One real solution
Use the quadratic formula to solve the equation:
2x2+3x-20= 0
x= 5/2
x= -4
7r2-14r=-7
7r2-14r+7=0 (divide everything by 7)
7(r2-2r+1)=0
7(r-1)(r-1)=0 so ...
r= 1
Write in vertex form and find the vertex using completing the square:
y= x2-2x-3
y= (x-1)2 - 4
VERTEX: (1, -4)
Solve each equation by taking square roots.
2(x+4)2=10
x= -4 +/- square root of 4
Find the discriminant of each quadratic equation then state the number of real and imaginary solutions.
9m2+6m+6=5
Discriminant: 0
One real solution
Use the quadratic formula to solve the equation:
4b2+8b+7=4
*remember it should equal 0 before you start!*
b= -3/2
2x2+7x-4=0
2(-4)=-8
Multiply to get -8, add to get 7
So 8 and -1
2x2+8x -1x-4
2x(x+4) -1(x+4)
(2x-1)(x+4)=0 so...
x= 1/2
x= -4
Solve the equation by completing the square.
5k2+20k=60
k= -6
Solve each equation by taking square roots.
(3x+1)2 - 36=0
x= 5/3, x= -7/3
Find the discriminant of each quadratic equation then state the number of real and imaginary solutions.
-9b2= -8b+8
Discriminant: -224
2 imaginary solutions
Use the quadratic formula to solve the equation:
2x2-3x-15= 5
*remember it should equal 0 before you start!*
x= 4
x= -5/2