All Student Take Calculus
Exact Values
SOHCAHTOA
Law of Sines & Cosines
Miscellaneous
100

For which quadrants are cos positive?

1 and 4

100

Find cos(45o)

1/root(2)

100

Define Sin, Cos, Tan in terms of opp, adj, hyp.

Sin=opp/hyp

Cos=adj/hyp

Tan=opp/adj

100

State one of the Laws of Cosine and the Law of Sines.

a2=b2 + c2-2bccos(A)   or

b2=a2 + c2-2accos(B)   or

c2=a2 + b2-2abcos(C)

and 

Sin(A)/a=Sin(B)/b=Sin(C)/c

100

Find two coterminal angles, one positive, one negative of 115o.

115o-360= -245o

115o+360= 475o

200

For which quadrants are sin positive?

1 and 2

200

Find sin(30o)

1/2

200

Define Sec, Csc, Cot in terms of opp, adj, hyp.

Sec=hyp/adj

Csc=hyp/opp

Cot=adj/opp

200

Solve for a if b=12, c=24, and angle A=40o.

a2 = 122+242-2(12)(24)cos(40o)

a = 16.7

200

If sin= 5/13, find cosand tan.

cos=12/13

tan=5/12

300

For which quadrants are cot positive?

1 and 3

300

Find cos(30o)

root(3)/2

300

Find the length of the opposite side.


10sin(35o) = 5.74

300

Solve for angle B if a = 7, b = 10, and c = 4.

102 = 42+72-2(4)(7)cos(B)

angle B = 128.7o

300

Find all six trig functions of an angle A whose terminal side passes through the point (-2,5).

tanA = 5/-2                  cotA = -2/5

cosA = -2/root(29)        secA = root(29)/-2

sinA = 5/root(29)          cscA = root(29)/5

400

For which quadrants are sec negative?

2 and 3

400

Find tan(135o)

-1

400

Find the length of the hypotenuse.

12/cos(42o) = 16.15

400

Solve for a if b=12, c=8, and angle B=40o.

Angle C = sin-1(8sin(40o)/12) = 25.4o

Angle A = 180o-40o-25.4o = 114.6o

a = 12sin(114.6o)/sin(40o) = 17

400
For what angle is the cotangent 2/3?

cot = 2/3, so tan = 3/2

tan-1(3/2) = 56.3o

500

For which quadrants are csc negative?

3 and 4

500

Find sin(300o)

-root(3)/2

500

Solve the entire triangle:


This is a 30o, 60o, 90o triangle, and the multiplier is 16.  Thus, the missing side is 16root(3).

500

Solve the triangle completely:

c2 = 82+102-2(8)(10)cos(45o) = 7.1

Angle B = sin-1(8sin(45o)/7.1) = 52.8o

Angle A = 180o-45o-52.8= 82.2o


500

Find the area of a triangle with side lengths 12 cm and 17cm, and an angle of 50o between them.

Use K=1/2(a)(b)sin(C)

1/2(12)(17)sin(50o) = 78.1 cm2

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