Angles and Radians
Graph Basics
Graph Transformations
Solving and Logic
Random
100

convert 135o to radians. Give your answer in terms of pi

(3pi)/4

100

Period of sinx

2pi

100

range of y = 4sin(x - pi/2)

-4<=y<=4

100

In which quadrants is cosecant (csc) positive?

Quadrant 1 and Quadrant 2 (same place sin is positive)

100

simplify cotxsecx

cscx

200

Angle of

(16pi)/3

Find a coterminal angle between 0 and 

2pi

(4pi)/3

200

Range of secx

y <=-1 uu y >=1

200

give three asymptotes of y = cot(x/2)

... ,-4pi, -2pi, 0, 2pi, 4pi, 6pi, ...

200

Which quadrant has cosx < 0 and cotx > 0?

Quadrant 3

200

Convert -3 radians to degrees

-171.89o

300

Find the reference angle for 

(16pi)/3

pi/3

300

Asymptotes between -2pi and 2pi for tanx

-3pi/2, -pi/2, pi/2, 3pi/2

300

Range of y = 5tan(3x - pi/6) + 4

All real numbers

300

If cos u = 1/3 and tan u < 0, find the value of u in degrees. Round to two decimal places

cos-1(1/3) = 70.53o but tan < 0 so should be in quadrant 4.

reference angle 70.53o

actual angle u = 360 - 70.53 = 289.47o

300

Find sinx and tanx if cosx = -3/5; 

pi < x< (3pi)/2

sinx = -4/5 and tanx = 4/3

400

Find the arc length: Circle with radius of 20 feet. Central angle of 75o. Round to two decimal places if needed. 

1. convert 75o to radians

2. s =

r*theta = (5pi)/12 * 20

 

Answer: 26.18 feet

400

What's the difference between tanx and cotx graphs?

tanx goes up, cotx goes down.

tanx goes through (0,0). cotx has an asymptote at x = 0

400

Write a sin equation for the graph below

y = -2sin(x-pi/3)-1

400

If cotx = -3 and sinx > 0, then secx = ?. Round to two decimal places

cotx < 0 and sinx>0 means x is in quadrant 2 and secx < 0

cotx = -3 --> tanx = -1/3 --> tan-1(-1/3) =-18.43o

Reference angle = 18.43.

sec(18.43) 1/cos(18.43) = 1.05 but said in quadrant 2, secx is negative 

final answer: - 1.05


400

sqrt(3)sectheta + secthetacottheta=0

theta = (5pi)/6 or (11pi)/6

500

A wind machine used to generate electricity has blades that are 10 feet in length. The propeller is rotating at four revolutions per second. Find the linear speed, in feet per second, of the tips of the blades.


1. convert from revolutions per second to radians per second (because revolutions isn't an exact distance) 

4rev/sec * 2pi rad/rev = 8pi rad/sec

2. v = rw

v = 10 * 8pi = 80pi feet/sec

3. Round to 251.33 feet/sec

500

What's the difference between secx and cscx graphs?

cscx has an asymptote at x = 0.

secx has a y-intercept at x = 0 (y = 1)

500

Write a sec equation for the graph below 

y = sec(3x) - 2

500

2sin^2x + 3sinx + 1 = 0

factor to get sinx = -0.4 or -1 . . . so 

x = (7pi)/6, (11pi)/6, or (3pi)/2

500

write a cosine function that has a midline of 2, amplitude of 3, period of 1 and a phase shift of 1/4 to the left. 

f(x) = 3cos(2pi(x+1/4))+2

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