Determine the quadrant in which θ lies when cosθ < 0 and cotθ > 0
Quadrant III
What is the period and amplitude of y = (5/2)sin(x)
period = 2π
amplitude = 5/2
What is the exact value of: cos(5π/2)
0
Given the following values of a right triangle:
A = 8.4o, a = 40.5
Solve for angle B. (State the answer in degrees rounded to three decimals)
B = 90o - 8.4o = 81.6o
Convert 3π/10 to degrees.
54o
What is the period of y = tan(x/3)
3π
What is the exact value of: csc(3π/4)
√2
Given the following values of a right triangle:
a = 2, c = 6
Solve for side b. (Rounded to three decimals)
b = √32 = 5.657
Determine the reference angle θ' of the angle θ = 205o
θ' = 25o
The point (π, -1) is on the graph of y=cos(x).
What transformed point will be on the graph of y=3(cos x + π)
(0, -3)
Shift left π units, and vertically stretch by a factor of 3
An acute angle θ is within a right triangle. The length of the side adjacent to θ is 24. The length of the side opposite to θ is 7.
Determine the exact value of cosθ
24/25
Given the following values of a right triangle:
B = 72.8o, a = 4.4
Solve for side b. (rounded to three decimals)
b = 4.4tan(72.8o) = 14.214
State two exact values of θ in degrees (0o < θ < 360o) such that cos(θ) = -√(3) / 2
θ = 150o and 210o
The point (π/2, 1) is on the graph of y = sin(x)
What transformed point will be on the graph of y=5+sin(πx)
(1/2, 6)
Horizontal shrink, and shift up 5 units.
The point (3, -4) is on the terminal side of an angle in standard position.
Determine the sine value of the angle.
sinθ = -4/5
A football lands at the edge of the roof of your school building. When you are 25 feet from the base of the building, the angle of elevation to the football is 21o. How high off the ground is the football?
Round the answer to three decimal places.
25tan(21o) = 9.597 ft
Determine two coterminal angles (one positive and one negative) to 5π/4
positive coterminal = 13π/4
negative coterminal = -3π/4
What is the range of the graph of y=4sin(x)
[-4, 4]
Determine the exact value of tanθ given:
cscθ = 3/2 and cosθ < 0
tanθ = -2√5 / 5
The height of an outdoor basketball backboard is 12.5 feet, and the backboard casts a shadow 17 feet long. What is the angle of elevation from the tip of the shadow to the top of the backboard? (State answer in degrees rounded to three decimal places.)
tan-1(12.5/17) = 36.327o