Degrees <-> Radians
Coterminal Angles, Arc Length, and Sector Area
Trig Ratios
Exact Values
Inverse Trig Functions
100

150o

5š›‘/6

100

Find at least one positive coterminal angle to -1140o

300o

100

What are the 3 basic trig rations?

sin=opposite/hypotenuse

cos=adjacent/hypotenuse

tan=opposite/adjacent

100

Find the exact value of sin(-š›‘/4)

-√2/2

100

What are the 3 inverse trig functions?

sin-1(opposite/hypotenuse)=šœƒ

cos-1(adjacent/hypotenuse)=šœƒ

tan-1(opposite/adjacent)=šœƒ

200

š›‘/3

60o

200

Find a positive AND negative coterminal angle to 3š›‘

š›‘ and -š›‘

200

If you have the adjacent of an angle and the hypotenuse, which trig ratio would you use to solve for the opposite?

cos

200

Find the exact value of cos(25š›‘/3)

1/2

200

Solve cos(cos-1(1/2))

cos(cos-1(x))=x if -1 ≤ x ≤ 1


Therefore the answer is 1/2

300

-520o

-26š›‘/9

300

What are the equations for arc length and sector area?

s=(šœƒ/2š›‘)(2š›‘r)=ršœƒ

area=(šœƒ/2š›‘)(š›‘r2)=1/2r2šœƒ


300

For angle x the opposite side is 12, the adjacent side is 5, and the hypotenuse is 13. Find cos(x).

cos=5/13

300

Find the exact value of tan(-3š›‘/4)

1

300

Solve sin-1(-1/2)

-š›‘/6

400

-41š›‘/12

-615o

400

A circle has a radius of 6 and a central angle of 48o. What is the arc length?

First turn the angle from degrees to radians=48(š›‘/180)=48š›‘/180=12š›‘/45

Then solve for arc length=s=6(12š›‘/45)=8š›‘/5

400

An angle of 70o has a hypotenuse of 5. Solve for the adjacent side(x).

cos(70)=x/5

5cos(70)=x

1.71=x

400

Find the exact value of sec(5š›‘/3)

2

400

Solve tan-1(1)

š›‘/4

500

-105o

-7š›‘/12

500

A sector with an angle of š›‘/6 and a radius of 12 cm. What is the sector area?

a=1/2(12)2(š›‘/6)

a=1/2(144)(š›‘/6)

a=(72)(š›‘/6)

a=72š›‘/6

a=12š›‘cm2

500

An angle of 65o has an adjacent side of 3, solve for the hypotenuse(x).

cos(65)=3/x

x(cos(65))=3

x=3/cos(65)

x=7.092

500

Find the exact value of csc(15š›‘/2)

-1

500

Solve sin(sec-1(13/5))

12/13

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