(3x2+5x-8)+(-5x2+7x+3)
-2x2+12x-5
-4(2x2yz3)2
-16x4y2z6
/2x+4/=8
x=2
x=-6
x2-5x-24
(x+3)(x-8)
2x2-10x-28=0
x=-2
x=7
(-4x3+7x2+2)+(-2x3-9x2+6x+1)
-6x3-2x2+6x+3
(4b+5)2
16b2+40b+25
/5a/+4=24
a=4
a=-4
10x2-7x-12
(5x+4)(2x-3)
24+2x-x2=0
x=-4
x=6
(7x2-8x-8)-(5x+4x2+9)
3x2-13x-17
(2x+7)(3x-5)
6x2+11x-35
/3x-6/>15
x>7 or x<-3
x4-16
(x+2)(x-2)(x2+4)
The length of a rectangle is 5 less than twice the width. Its area is 187 in2. What are the dimensions?
11 in by 17 in
(2x2y+7xy2-3xy+5x+4y)+(-5x2y-2xy2+7xy-6x-3y)
-3x2y+5xy2+4xy-x+y
(3x+2)(4x2+7x-5)
12x3+29x2-x-10
/6x+12/-7<23
-7<x<3
4x2-28x+48
4(x-4)(x-3)
x2+8x=0
x=0
x=-8
(2abc2-4a+5bc+10b2c)-(8abc2-7a-2bc+5b2c)
-6abc2+3a+7bc+5b2c
The length of a rectangle is 5 more than 3 times the width, x. Find a formula for its area in terms of x.
3x2+5x
/-2x+8/<44
-18<x<26
6a3-10a2+9a-15
(2a2+3)(3a-5)
3x(x-10)+80=5
x=5