CH 16
CH 17
Solubility
Past Exams
Past Exams
100

A conjugate acid of H2O is

A- H3O+
B- OH-
C- H+
D- H2O
E- D2O

H3O+

100

Which solution below would have the lowest concentration of hydroxide ions?

A- pH=7.93
B- pH=7.00
C- pH=12.6
D- pH=3.22
E- pH=9.84

pH=3.22

100

Ferrous hydroxide is a slightly soluble base. Which of the following would dissolve Fe(OH)2 the least effectively?

A- 0.1 M HCl
B- 0.1 M HNO3
C- 0.1 M HNO2
D- 0.1 M H2SO4
E- 0.1 M HI

0.1 M HNO2

100

A 0.1M aqueous solution of _______ is acidic at 25oC?

A- KCl
B- Mg(OAc)2
C- CsNO3
D- NH4Cl
E- NaOCl

NH4Cl

100

Which of the following could be added to a solution of sodium acetate to produce a buffer?

A- sodium chloride or potassium acetate
B- acetic acid only
C- hydrochloric acid only
D- potassium acetate only
E- acetic acid or hydrochloric acid

acetic acid or hydrochloric acid

200

Which of the following is the weakest acid:

A- 2-hydroxybenzoic acid Ka =1.1x10-3
B- ascorbic acid Ka=1.0x10-6
C- 3-chlorobenzoic acid Ka=1.5x10-4
D- benzoic acid Ka=6.5x10-5
E- chloroacetic acid Ka =1.0x10-2

ascorbic acid Ka=1.0x10-6

200

Consider the diagram of the titration curve shown above. What type of substance was originally in the flask?

A- weak base
B- weak acid
C- strong bace
D- strong acid

strong base

200

In what order would the following compounds precipitate out if they had the same concentration?

PbSO4 (Ksp=1.8x10-18)
PbCrO4 (Ksp=1.8x10-5)
PbO (Ksp=7.3x10-22)

PbO, PbSO4, PbCrO4

200

Buffers in the human body______.

A- precipitate proteins so enzymes are inactive
B- help keep the body temperature constant
C- help change the blood plasma pH when foods are eaten
D- all of the above
E- none of the above

none of the above; help to maintain a constant blood pH

200

Acids that ionize extensively in solution are referred to as:

A- weak acids
B- lewis acids
C- bronstead-lowry acids
D- strong acids
E- Arrhenius acids

strong acids

300

Identify the acid, base, conjugate acid, and conjugate base in the following reaction:

H2O + HCO3- <-> OH- + H2CO3

Acid: H2O
Base: HCO3-
C. Acid: H2CO3
C. Base: OH-

300

Calculate the pH of a solution prepared by dissolving 0.625 mol of NH3 and 0.375 mol of NH4Cl in water sufficient to yield. 1.000L of solution. The Kb of ammonia is 1.77x10-5

Necessary equations:
Kw=1.00x10-14
pH=pKa + log [acid]/[base]

9.470

300

The solubility product, Ksp, for Ca(OH)2 is given by the expression:

A- [Ca][OH]2
B- [Ca2+][OH-]2
C- [Ca2+] x 2[OH-]
D- [Ca2+][OH-]2/[Ca(OH)2]
E- [Ca(OH)2]/[Ca2+][OH-]2

[Ca2+][OH-]2

300

BF3 is a ________.

A- Bronsted acid
B- Bronsted base
C- Lewis base
D- Lewis acid
E- Arrhenius base

Lewis acid

300

What is the pH of 1.8x10-2 M NaOH at 25oC?

12.3

400

What is the H+ concentration of a solution with a pOH of 3.45?

Necessary equations:
pH + pOH = pW

2.82x10-11

400

The Ka of HClO is 3.0x10-8 at 25oC. Calculate the pH of 0.8349 M acidic solution.

Necessary equations:
ICE chart
[H+] or [OH-] = [products][/[reactants]

3.80

400

The Ksp for Au2S is 1.0x10-39. What is the molar solubility of Au2S?

6.3x10-14

400

An aqueous solution contains 9.2x10-2 M KOH at 25oC. The pH of the solution is?


12.96

400

What is the pH of a mixture containing 0.42 M HNO2 and 0.21 M NaNO2? Ka for HNO2=4.5x10-4

Necessary equations:
pH=pKa + log[base]/[acid]

3.05

500

What is the pH of a 0.176 M ammonia (NH3) solution at 25oC? Kb (NH3) = 1.8x10-5

Necessary equations:
K = [product]/[reactant]
-log[pH]=H+

11.25

500

The pH of a 0.70M solution of a weak base is 10.2. What is the Kb for this base?

Necessary equations:
pH + pOH = 14
-log[pH]=H+
ICE chart

3.6x10-8

500

What is the molar solubility of Al3+ in a solution that is buffered at a pH of 3.00? Ksp Al(OH)3=4.0x10-15

Necessary equations:
ICE chart
Ksp=[product]/[reactant]
pH+pOH=14

4x10-18

500

A solution of KCl is added dropwise to a solution that is 0.093 M in Mg2+. When the concentration of Cl- exceeds _______M, MgCl2 will precipitate. Neglect volume changes. For MgCl2, Ksp=2.2x10-10

Necessary equations:
pH+pOH=14
Ksp=[products]/[reactants]

4.86x10-5

500

At 35oC, the equilibrium constant for the reaction below is Kc=2.5x10-8

2NOCl <-> 2NO + Cl2

An equilibrium mixtrue was found to have [Cl2]=2.0x10-3M and [NOCl]=1.2x10-4M. Calculate the concentration of NO at equilibrium. 

Necessary equations:
Keq=[products]/[reactants]

3.87x10-5

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