Solve the Equation
Write the Algebraic Expressions
How Many Solutions?
Identify the Property
Challenge
200

Solve the equation:

x-3-3x=-13

x=5

200

Half of a number is equal to seventeen.

1/2x=17

200

7x-5=12x-5

One

200

3x+4=4+3x

Commutative Property of Addition

200

Solve the equation:

frac{4(x+3)}{6}=8

x=9

400

Solve the equation:

3(8x+2)=198

x=8

400

The difference of a number twice x and four is 12 more than the number x.

2x-4=x+12

400

3(x+4)=4+3x

Many


400

5(x+9)-13

Distributive Property

400

Determine the number of solutions for the equation below and prove you are correct by solving the equation.

3(x+5)-6x=4x-13

One Solution

x=4

600

Solve the equation:

-7(1-8n)=105

n=2

600

DOUBLE YOUR POINTS!

Two times the difference of a number and sixteen plus four is twenty-seven more than a number.

2(x-16)+4=x+27

600

-30+4x=4x-30

None


600

a*(b*c)=(a*b)*c

Associative Property of Multiplication
600

Simplify the radical in simplest form:

sqrt352

4sqrt22

800

DOUBLE YOUR POINTS!

Solve the equation:

6(x-3)=10x-18

x=0

800

Five less than four times a number is ten subtracted from that number.

4x-5=x-10

800

8x-12=2(2x+6)

one

800

3x+5=18

3x+5-5=18-5

Subtraction Property of Equality

800

Name and give and example the three properties we have previously learned about.

3+5=5+3
           3*5=5*3

Commutative Property of addition and multiplication

(2+3)+4=2+(3+4)
           (2*3)*4=2*(3*4)

Associative Property of addition and multiplication

a(b+c)=ab+bc

Distributive Property

1000

Solve the equation:

-4(1+4x)-6x=-180

x=8

1000

One third the sum of a number and eighteen is equal to twelve subtracted from the number.

1/3(x+18)=x-12

1000

9x-2=1/2(18x-4)

Many

1000

TRIPLE YOUR POINTS!!

4(x-2)=12

4x-8=12

4x-8+8=12+8

Distributive Property 

Addition Property of Equality

1000

DOUBLE YOUR POINTS! IF YOU ARE WRONG, LOSE ALL YOUR POINTS!

Translate to an algebraic expression.

Francisco is three years more than twice Jenna's age. Harrison is two years less than three times Jenna's age. If Jenna's age is given by a, then write an expression for Francisco's age, Harrison's age, and the sum of all three ages, in terms of a.

Jenna's Age:

Francisco's Age: 

Harrison's Age: 

Sum of All Three Ages:


2a+3

3a-2

6a+1

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