2.6
P1
3.1
3.2 ex 1
3.2 ex 2
100

Identify the explanatory variable and the response variable in this study.

Explanatory: Distance

Response: Fee

100

Who are the cases?

College Students

100

what would we have to do to calculate the parameter exactly? 


ask all college students if they drink coffee daily

100

Give notation for the parameter being estimated.

 ๐‘1 โˆ’ ๐‘2

100

Based on the sample, what is the value for best estimate?

"x-bar" = 5.4

200

Use the regression line equation to predict the total delivery fee for a restaurant located 5 miles away.

$12.75

200

What is the probability that an employee chosen at random is Contract and prefers the Night Shift?

0.0857

200

Use the distribution to estimate the proportion of all college students who drink coffee daily. Give correct notation for your answer.

0.65

200

Calculate the difference in sample proportions (streaming minus cable) using three decimals and include appropriate notation

โˆ’ 0. 080

200

Give notation for the parameter being estimated and define the parameter within context.

"mu" = the average smartphone screen time of college students

300

An observed fee at 5 miles was $11.50. Calculate the residual

-$1.25

300

What is the probability that an employee chosen at random is Part-Time or prefers the Day Shift?

0.6

300

Suppose we take another random sample. Based on the graph, how likely are we to see a result that matches each of the following sample proportions?
(Choose from: (i) reasonably likely to occur, (ii) unusual (rare) but might occur, or (iii) unlikely to ever occur)

p  = 0.50 , p = 0.65 , p = 0.72 , p = 0.88

p = 0.50 : (iii) unlikely to ever occur 

p = 0.65: (i) reasonably likely to occur 

p = 0.72: (ii) unusual (rare) but might occur 

p = 0.88: (iii) unlikely to ever occur

300

Calculate a confidence interval given that the standard error ( ๐‘†๐ธ) for the difference in proportions is 0.024.



โˆ’ 0. 128 to โˆ’ 0. 032

300

Calculate a 95% confidence interval given that the standard error of the estimate (SE) is about 0.3 hours.

4.8 to 6.0

400

Interpret the value of the slope in the context of this study.


For each increase in distance, the fee may increase by 1.80.

400

If an employee is Full-Time, what is the probability that they prefer a Rotating Shift?

0.1667

400

What does one dot on the dotplot represent? Include correct notation.



One dot represents 200 college students and a sample proportion

400

Based on the interval, is it plausible that there is โ€œno differenceโ€ in the proportions between streaming-only and traditional cable users? Explain.

no, 0 is not contained in the interval estimate

400

Based on the interval estimate, is it reasonable to say that the average daily smartphone screen time might be 5?

Yes, 5 is contained in the interval estimate

500

Interpret the value of the intercept in the context of this study.

If distance traveled was 0, the fee might be $3.75

500

What is the probability that an employee is Part-Time if they prefer the Night Shift?

0.3571

500

Give notation for the parameter and define the parameter within the context of the study.

P = The proportion of all college students that drink coffee daily.

500

Interpret the confidence interval in context. 

We are 95% confident that the true difference in the proportion of all streaming-only users and traditional cable users who prefer live events is between -0.128 and -0.032 

500

Interpret the confidence interval in the context of the study.

We are 95% confident that the average daily smartphone screen time for all college students is between 4.8 hours and 6.0 hours.





M
e
n
u