Factor completely.
2x^3+6x
2x(x^2+3)
Simplify
i^2
-1
What is the quadratic formula?
x = (-b pm sqrt(b^2-4ac))/(2a)
What are the solutions of this parabola?
x=-4, x=-2
Expand.
(2x-3)^2
4x^2 -6x+9
Factor completely.
x^2-3x-18
(x+3)(x-6)
Simplify
(8-7i)+(3-2i)
11-9i
Solve using the quadratic formula:
x^2+3x-1=0
(-3 pm sqrt(13))/2
Solve.
x^2-3x-4
x=4, x=-1
Solve
x^2=9
x=3 and x=-3
Factor completely.
2x^2+5x-3
(2x-1)(x+3)
Simplify
(-6-6i)-(5+5i)
-11-11i
Solve using the quadratic formula.
x^2+4x+5
(-4 pm 2i)/(2) = -2 pm i
Solve.
x^2-5=4
x=+-3
Simplify.
sqrt(20)
2sqrt(5)
Factor completely.
2x^3-8x^2+x-4
(2x^2+1)(x-4)
Simplify
(3+3i)(2+5i)
-9+21i
The discriminant (b2-4ac) is positive/negative/0 (choose one) so there are ______ real solutions.
The discriminant is positive so there are 2 real solutions.
Solve.
(x+3)^2=16
x=1,-7
Solve.
x^2 = -9
x=3i and x=-3i
Factor completely.
x^3+ -2x^2-x+2
(x+1)(x-1)(x-2)
Simplify
(4+3i)(2-i)
11+2i
The discriminant (b2-4ac) is positive/negative/0 (choose one) so there are ______ real solutions.
The discriminant is 0 so there is 1 real solution.
Solve (Hint: you will get complex solutions)
(x-2)^2+3=-6
x=2+-3i
Simplify.
(x-2)^2 = -27
x=2+-3isqrt(3)