Absolute Value Equations & Absolute Value Inequalities
When do you flip the sign of an inequality?
When you multiply or divide by a negative number
What type of line and where do you shade for <?
Dashed line and shade below
Which line is steeper:
y=-8x + 9 or y=4x + 100 or y=-6x + 40 or y=6x-52
y=-8x+9
(4x2 + 2x) + (x2 + 6x)
5x2 +8x
3x2(2x - 4)
3x2(2x - 4)
Solve: |2x + 5| > 19
x > 7 or x < -12
How would the line for the following look and where would you shade?
y< 3x-7
solid line and below the line
g(x) = 3x - 1; Find g(x)=5
x = 2
(2a2 - 7a + 10) + (a2 + 4a + 7)
3a2 -3a +17
(x + 4)(x - 2)
x2 + 2x - 8
How do you graph the following y > -x + 8?
(type of line, where do you shade, y-intercept, and slope)
Dashed line, shade above, y-intercept=8 and the slope is -1
The graph of y = | x | - 2
(how does it open, what is the vertex, what is a)
opens up, vertex (0,-2), a= 1
(-3a2 - 2a) - (4a2 - 4)
-7a2 - 2a + 4
(4m + 2)(4m + 5)
16m2 + 28m + 10
How do you graph the following: y < 2/3 x - 4
(type of line, where do you shade, y-intercept, and slope)
dashed line, shade below, b=-4, m=2/3
The graph of y = | x - 3| + 4
(how does it open, what is the vertex, what is a)
opens up, vertex (3, 4), a=1
(4x3 + 5x + 2) - (1 + 2x - 3x2)
4x3 + 3x2 +3x + 1
(5b − 6)(5b2 + 4b − 2)
25b3 − 10b2 − 34b + 12
How do you graph the following: y<-3
(type of line, where do you shade)
solid horizontal line, below(down)
The graph of:
y = -3 |x + 2| + 5
opens down, vertex (-2,5) a=-3/1
(4 - x - 2x2) - (-2 + 3x - x3)
x3 - 2x2 - 4x + 6
(2x3y4)(5xy)
What is 10x4y5?