FOIL
Functions
Finding the zeros
Equations from zeros
Misc.
100
(x+3)(x+5)
x2+8x+15
100
Solve: for f(0)
f(x)=3x2-33x+84
f(0)= 84
100
h(x) = 0.02(x-1)(x-7)
Zeros are x=1 and x=7
100
(x+4)(x-2)
x2+2x-8
100
The term domain defines what part of your graph?
the x-axis/ the input
200
(x−4)(x+7)
x2+3-28
200
Solve: for f(-2)
f(x)=3x2-33x+84
f(-2)= 162
200
g(x)= 0.05(x-3)(x-8)
Zeros are x=3 and x=8
200
(x+10)(x-15)
x2-5x-150
200
The term range defines which part of your graph?
the y-axis/ the output
300
(x−6)(x−2)
x2-8x+12
300
Solve: for f(10)
f(x)=3x2-33x+84
f(10)= 54
300
m(x)= x2-7x+10
zeros are x=2 and x=5
300
Write the quadratic equation for this given graph
x2-3x-10
300
Write an equation that represents the area of this rectangle.
4x2+100x+600
400
(2x+3)(x−5)
2x2-7x-15
400
Solve: for f(-5)
f(x)=3x2-33x+84
f(-5)= 324
400
h(x)= 2x2-18x+36
zeros are x=3 and x=6
400
x2-2x-3
400
Which graph type will eventually always have a larger output?
Quadratic or Exponential
Exponential
500
(3x−4)(2x+5)
6x2+7x-20
500
Solve: for f(-16)
f(x)=3x2-33x+84
f(-16) = 1380
500
(x+8)(x-5)
zeros are x=-8 and x=5
500
If your graph has two negative zero values what would the format or your quadratic function be?
ax2+bx-c
ax2+bx+c
ax2-bx+c
ax2+bx+c
500
(f-m)(b+jh)
fb+fjh-mb-mjh