Unit 7 Review

7A

100

The transformations of

y=2^{(x-5\)}-4

What is 5 right and 4 down?

200

The inverse of y=log₃x

What is y=3^x ?

300

Growth or Decay and the rate:

y=(1.07)^4

What is 7% growth?

400

Growth or Decay and the rate:

y=2(0.68)^3

What is 32% decay?

500

Growth or decay:

y=1/2e^(3x)

What is growth?

7B

100

Exponent form of

Log_(3)(1/3)=-1

What is 

3^-1=1/3

200

Log form of:

25=5^2

What is 

log_(5)25=2

300

*DAILY DOUBLE*

The value of m:

Log_(6)m=0

What is 1?

400

The value of m:

Log_(7)(1/49)=m

What is -2?

500

The value of m:

Log_(m)(-25)=2

What is undefined?

7C

100

Condense:

Log_(4)(7)+Log_(4)(x)

What is 

Log_(4)(7x)

200

Condense:

log_(5)8-log_(5)x

What is 

log_(5)(8/x)

300

Expand:

ln(m^2p)

What is

2lnm + lnp

400

Expand:

log_(7)((ab)/c^3)

What is

log_(7)a+log_(7)b-3log_(7)c

500

Expand:

log_(2)(32xy^3)

What is

5+log_(2)x+3log_(2)y

7D

100

Solve to the nearest hundredth:

6^x=120

What is x = 2.67 ?

200

Solve for x.

log_(4)(3x-5)=log_(4)(x+17)

What is x = 11 ?

300

Solve to the nearest tenth:

e^(2x-1)=18

What is x = 1.9 ?

400

Solve for x:

(1/2)^(x-6)=4^x

What is x = 2 ?

500

Solve for x:

log(4)+log(x-5)=2

What is x = 30 ?

7E

100

The equation for:  "The value begins at $250 and decreases by 17% each year for five years." 

What is 

y=250(0.83)^5

200

The equation for: "$1000 is deposited into an account earning 4% interest compounded continuously for 3 years."

What is 

A=1000e^(0.04*3

300

The amount you have after depositing $100 into an account earning 5% interest compounded monthly for 3 years.

What is $116.15 ?

400

The number of years it takes for $300 to double when the account earns 6% compounded continuously.

What is 11.6 years ?

500

The number of hours it takes for 500 cells to become 10 cells if they decrease at a rate of 37% per hour.

What is 8.5 hours ?