Inequalities
Simplifying
Geometry
Miscellaneous
100

Describe the solution set of the conjunction:

x< 4 and x > 6

No solutions


100

Simplify:

(x+5)^2

x^2+10x+25

100

What is the volume of a cube 5 inches on each side?

125 in3

100

Two sides of a triangle are 9 inches and

4sqrt5

 inches long.  The third side must measure betweeen ______ and ______ inches.  

4 and 24

200

Describe the solutions in interval notation:

x< 4 or x > 6

(-oo, 4) (6, oo)

200

Simplify, and write your answer as a simple fraction without parentheses:  

x^2/(x^2+5x-36)-2/(x-4)

(x^2-2x-18)/(x^2+5x-36)

200

What is the surface area of a hemisphere of radius 5 meters?

75pi  m^2

200

Multiply:

(2x^2-7)(5x-3)




10x^3-6x^2-35x+21

300

Describe the solution set of the conjunction:

-5 > -2x + 7 > -9, x in ZZ

{7}

300

Simplify:  

(x^2- 5x - 14)/(x^2 - 4)-:(x^2-10x+21)/(x-2)

1/(x-3)

300

What is the measure of a single interior angle of a regular octagon?

135 degrees

300

Solve:  

abs(x+5)=8

x = -13 or x = 3

400

Write a negation for the statement:

2.5 is an even number.  

2.5 is not an even number. 

400

Find the quotient using long division:

(x^3-5x+8)div(x-2)

x^2+2x-1+6/(x-2)

400

What is the surface area of a cone of height 12 meters and and radius 5 meters?

90pi   meters^2

400

State the solution set in interval notation:   

-2abs(x) < 8

(-oo,oo)

500

Describe the solutions in interval notation: 

x < -2 and x < 0

(-oo,-2]

500

Simplify:  

5/(7sqrt3-1)

(35sqrt3+5)/146

500

What is the surface area of a pyramid with a square base 10 meters on each side if the height is 12 meters?

360 meters^2

500

Simplify:   

sqrt(200)-sqrt(50)+sqrt2(7+sqrt6)(7-sqrt6)

48sqrt2

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