Molar mass, mass and moles
Particles and moles
Mass Percent Composition
Dilution
Molarity
100

To find number of moles from number of grams, you would use ______

molar mass of a molecule

100

To convert between from number of moles and Number of particles, you would use ______

Avagadro's Number=6.022 x1023

100

What is the first step you need to do to figure out the percent composition by mass of a molecule?

  1. Find the molar mass of all the elements in the compound in grams per mole.                              *the following steps are below*
  2. Find the molecular mass of the entire compound.
  3. Divide the component's molar mass by the entire molecular mass.
  4. You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.
100

What is the formula for Dilution?

M= Initial Molarity

V1= Initial Volume

M2= Final Molarity

V2=Final Volume


100

The correct definition for molarity is ______divided by ___.

 moles solute/L solution

200

What is the molar mass of H2S (in g/mol)?

34.086 g/mol

*add molar mass of 2 H and 1 S 

200

How many mol of hydrogen atoms are in 0.203 mol of Fe(OH)3 ?

0.609 mol

*Take 0.203 and multiply by the # of H atoms (3)/ # of Entire molecule (1)

200

A sample of a compound is decomposed and found to contain 9.01 g of S and 4.50 g of O.  What is the empirical formula of this compound?


SO

*1st step: take S and O and convert each to mols

2nd step: You will see it comes out to 0.28 mol S and 0.28 mol O which is 1:1 ratio

200

You have a concentrated solution of compound Z.   You take a small volume of this solution, and add it to a much larger volume of water to make a new solution.

 Which of the following is true about the new solution?

Group of answer choices

A. It is less concentrated than the original solution

B. It is more concentrated than the original solution

C. It has the same concentration as the original solution

A. It is less concentrated than the original solution

200

What is the molarity of a solution that has 1.75 mol of sucrose in a total of 4.85 L of solution?

0.3608 M

*1.75 mols/ 4.85 L

300

What is the mass of a single atom of krypton (Kr)?

1.39 x 10-22 g

*first take molar mass then divide by avagadro's number

300

You have 8.7319 x1023 particles of Hydrogen. How many moles are there?

1.45 Moles

*divide by avagadro's number

300

What is the mass percent of Fe in iron(II) bromide       ( FeBr2 ) ?

25.9% Fe

*First find molar mass of Fe and Br2 

Then divide MM of Fe by total molar mass.


300

You have a concentrated solution  of 5.00 M NaOH.  If you dilute 98.5 mL of this solution with water to a final volume of 2.00 L, what is the molarity of the diluted solution?

0.246 M

*Remember to convert mL to L

*Plug into dilution formula

300

A 2.00 M solution contains 3.50 mol of the solute.  What is the volume (in L) of this solution?

1.75 L

*Take 3.5 mol and divide by 2 M

400

What is the mass (in g) of 0.935 mol of aluminum?

25.2 g

*You would take 0.935 mol and multiply by the molar mass of Al, which is 26.98 g/mol

400

How many protons are in 7.91 x 10-22 g of F?

226

*You will need to convert from Mass to moles to particles to protons

400

A compound was decomposed and determined to be 55.16 % C, 8.10 % H and 36.74 % O by mass.  What is the subscript for H in the empirical formula for this compound? 

7 (H7)

*Review Determining Formula From Percent Composition video if this is difficult

*Tip: 

1. Assume 100g sample then convert to mols. 

2. From moles, divide each by smallest number (0.02296 mol O)

3. Multiply all by 2


400

You have a concentrated solution  of 5.00 M NaOH.  If you dilute 135.5 mL of this solution with water to a final volume of 2.00 L, what is the molarity of the diluted solution?

0.339 M

400

What volume (in mL) of 5.00 M HCl must diluted to a final volume of 1.50 L to make a solution with a final concentration of 0.450?

135 mL

*Remember that equation is asking for answer in mL so convert 0.135 L to 135 mL

500

How many mol of hydrogen atoms are in 0.203 mol of Fe(OH)3 ?

0.609

500

You have measured out 75.00 g of Mg(OH)2 (formula weight: 58.33 g/mol) to make a solution.  What must your final volume be (in L) if you want a solution made from this mass of Mg(OH)2 to have concentration of 0.245 M?

5.25 L

*Find moles from 75.00g and 58.33 g/mol

might help to set up equation like L=Moles/Molarity

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