MEAN
MEDIAN, MODE, RANGE
OUTLIERS
TRUNCATED MEAN
BEST MEASURE OF CENTRALITY
100

A student scored 70, 80, and 90 on three quizzes.
What is the average score?

80

100

Find the median:

2, 5, 9, 12

7
100

Which number is the outlier?
5, 6, 7, 8, 42

42

100

What do you remove when finding a truncated mean?

Extreme values / outliers

100

If data has no outliers, which measure is usually best?

Mean

200

Find the mean of:
4, 7, 9, 10, 15

9

200

Find the mode:
4, 6, 6, 8, 9, 9, 9

9

200

Does an outlier usually affect the mean or the median more?

Mean

200

Find the truncated mean after removing the highest and lowest values:
5, 6, 7, 8, 30

7

200

Which measure is least affected by outliers?

Median

300

The average of 5 numbers is 12.
The first four numbers are 8, 10, 14, and 11.
What is the fifth number?

12 × 5 = 60

8 + 10 + 14 + 11 = 43

60 − 43 = 17

300

Find the median:
3, 5, 7, 8, 10, 12

7.5

300

A class has scores:
80, 82, 84, 85, 10

Would the median or mean better describe the class performance?

10 is a very low outlier.

Mean gets pulled down.

Median better shows typical scores.

300

Judges give scores of 8, 8.5, 9, 6, and 9.5. Find the truncated mean.

  • Remove highest score.
  • 9.5
  • Remove lowest score.
  • 6
  • Add remaining values.
  • 8 + 8.5 + 9 = 25.5
  • Divide by 3
  • 25.5 ÷ 3 = 8.5
300

A store sold shoe sizes:
9, 9, 9, 10, 11

Which measure helps most when restocking?

mode

400

The mean of 8 numbers is 15. Seven of the numbers are.

12, 13, 15, 16, 17, 18, 19

15 × 8 = 120

12 + 13 + 15 + 16 + 17 + 18 + 19 = 110

120 − 110 = 10

10, not an outlier

400

A data set has:

  • Median = 12
  • Range = 18

The smallest number is 4 and there are exactly 5 values.

Create one possible data set.

Range = 18

Largest = 22

Median = 12

Middle value must be 12

Build a valid set: 4, 8, 12, 15, 22

Answer: 4, 8, 12, 15, 22   or 4, 10, 12, 18, 22  or 4, 11, 12, 13, 22   or 4, 5, 12, 21, 22  or 4, 12, 12, 12, 22

400

Data Set A:
25, 78, 24.5, 28, 29

Data Set B:
31, 40, 50.5, 28, 34

Without calculating the mean, determine which set has the larger mean and explain.

Data A: 25 + 78 + 24.5 + 28 + 29
= 184.5

Data B: 31 + 40 + 50.5 + 28 + 34
= 183.5

Data A is larger.

400

A diving score uses a truncated mean.

Judges give:
9.5, 7.5, 7.5, 7.0, 8.0, 5.5

Find:

a) Mean
b) Truncated Mean

A) (5.5 + 7 + 7.5 + 7.5 + 8 + 9.5) ÷ 6
= 45 ÷ 6
= 7.5

B) Remove 5.5 and 9.5

(7 + 7.5 + 7.5 + 8) ÷ 4
= 30 ÷ 4

400

A basketball player scores:

0, 22, 23, 24, 25, 26, 27

Which measure best describes their typical performance?

median

500

Five numbers have a mean of 20.

Four numbers are:
14, 18, 22, 24

A sixth number is added and the mean stays exactly 20.

What number was added?

20 × 5 = 100

14 + 18 + 22 + 24 = 78

100 − 78 = 22

78 + 22 = 100

20 × 6 = 120

120 − 100 = 20

500

A set of 7 numbers has:

Mean = 10

Median = 10

Mode = 10

What is the largest possible value in the set?

  • Total must be: 10 × 7 = 70
  • To maximize the largest value, make other numbers as small as possible.
  • Since mode is 10:
  • Need at least two 10s.
  • Since median is 10: 
  • Middle number must be 10.
  • Use: 1, 2, 3, 10, 10, 18, x
  • Add known numbers: 1 + 2 + 3 + 10 + 10 + 18 = 44
  • Find x: 70 − 44 = 26
500

A data set has 8 numbers with a mean of 42.

One number is removed from the data set, and the new mean becomes 36.

You are told the removed value is one of the following:

  • 30
  • 50
  • 70

 Which value was removed? Show working and justify your answer.

42×8=336

36×7=252

336 - 252 = 84

None of the options are correct.

500

Create a data set of 5 numbers where:

  • Mean = 20
  • Truncated Mean = 15

5, 10, 15, 20, 50

Mean:
(5 + 10 + 15 + 20 + 50)
= 100

100 ÷ 5 = 20

Truncated Mean:
Remove 5 and 50

10 + 15 + 20 = 45

45 ÷ 3 = 15

other solution: 7, 12, 15, 18, 48   or 5, 10, 20, 20, 45   or 2, 13, 14, 18, 53 

500

Three students have the following test scores:

Student A:

72, 78, 80, 82, 88

Student B:

80, 80, 80, 80, 80

Student C:

60, 70, 80, 90, 100

Task:

  1. Identify which student is most consistent overall
  2. Identify which student is least consistent overall
  • Student A: 88 − 72 = 16
  • Student B: 80 − 80 = 0
  • Student C: 100 − 60 = 40

So:

  • Smallest spread → B
  • Largest spread → C
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