Complement Q 1
The complement of an angle is 15 more than twice the angle.
Set up the equation.
x is the angle
90 - x = 15 + 2x
The supplement of an angle is 12 less than 3 times the angle.
Set up the equation.
x is the angle
180 - x = 3x - 12
Five times the complement is 6 more than twice the supplement. Set up the equation.
x is the angle
5(90-x) = 6 + 2(180-x)
∠A and ∠B are vertical angles. If m∠A=(5x−9)∘ and m∠B=(8x−30)∘
write the equation.
vertical angles are congruent
m∠A = m∠B
5x - 9 = 8x - 30
∠A and ∠B are complementary angles. If m∠A=(6x+22)∘ and m∠B=(7x+16)∘,
write the equation.
m∠A + m∠B = 90
6x + 22 + 7x + 16 = 90
∠A and ∠B are supplementary angles. If m∠A=(8x−25)∘ and m∠B=(7x−5)∘,
write an equation.
supplementary sums to 180 degrees
m∠A + m∠B = 180
8x - 25 + 7x - 5 = 180
∠A and ∠B form a linear pair. If m∠A=(2x+8)∘ and m∠B=(2x+8)∘, then which of the following apply?
∠A and ∠B are...
congruent - adjacent - complementary - supplementary - vertical angles
∠A and ∠B are...
congruent - adjacent - supplementary
The complement of an angle is 15 more than twice the angle. Find the angle.
90 - x = 15 + 2x
x is the angle
75 = 3x
x = 25 degrees
The supplement of an angle is 12 less than 3 times the angle. Find the angle.
180 - x = 3x - 12
4x = 192
x = 48 degrees
Five times the complement is 6 more than twice the supplement.
Find the angle.
5(90-x) = 6 + 2(180-x)
5(90-x) = 6 + 2(180-x)
450 - 5x = 6 + 360 - 2x
84 = 3x
x = 28 degrees
∠A and ∠B are vertical angles. If m∠A=(5x−9)∘ and m∠B=(8x−30)∘
5x - 9 = 8x - 30
Solve for x.
5x - 9 = 8x - 30
21 = 3x
x = 7
∠A and ∠B are complementary angles. If m∠A=(6x+22)∘ and m∠B=(7x+16)∘,
solve for x. 6x + 22 + 7x + 16 = 90
6x + 22 + 7x + 16 = 90 combine like terms
13x + 38 = 90
13x = 52
x = 4
∠A and ∠B are supplementary angles. If m∠A=(8x−25)∘ and m∠B=(7x−5)∘, solve for x.
8x - 25 + 7x - 5 = 180
8x - 25 + 7x - 5 = 180 combine like terms
15x - 30 = 180
x = 14
∠A and ∠B form a linear pair. If m∠A=(2x+8)∘ and m∠B=(2x+8)∘, write the equation.
linear pairs are supplementary 180 degrees
m∠A + m∠B = 180
2x + 8 + 2x + 8 = 180
The complement of an angle is 15 more than twice the angle. Find the complement.
90 - x = 15 + 2x
x = 25 degrees
90 - 25 = 65 degrees is the complement
The supplement of an angle is 12 less than 3 times the angle. Find the supplement.
180 - x = 3x - 12
x = 48 degrees
180 - 48 = 132 degrees
Five times the complement is 6 more than twice the supplement.
Find the complement.
x = 28 degrees
90 - 28 = 62 degrees
∠A and ∠B are vertical angles. If m∠A=(5x−9)∘ and m∠B=(8x−30)∘
5x - 9 = 8x - 30
Solve for m∠A. x = 7
m∠A = 5(7) - 9 = 26 degrees
∠A and ∠B are complementary angles. If m∠A=(6x+22)∘ and m∠B=(7x+16)∘,
solve for m∠A and m∠B. 6x + 22 + 7x + 16 = 90
x = 4
m∠A=6(4)+22 = 46 degrees
m∠B=7(4)+16= 44 degrees
∠A and ∠B are supplementary angles. If m∠A=(8x−25)∘ and m∠B=(7x−5)∘, solve for m∠A and m∠B.
x = 14
m∠A = 8x - 25 = 8(14) - 25 = 87 degrees
m∠B = 7(14) - 5 = 93 degrees
∠A and ∠B form a linear pair. If m∠A=(2x+8)∘ and m∠B=(2x+8)∘, solve for x.
2x + 8 + 2x + 8 = 180
2x + 8 + 2x + 8 = 180
4x + 16 = 180
4x = 164
x = 41
Five times the complement is 6 more than twice the supplement.
Find the supplement.
x = 28 degrees
180 - 28 = 152 degees
∠A and ∠B are vertical angles. If m∠A=(5x−9)∘ and m∠B=(8x−30)∘
5x - 9 = 8x - 30
Solve for m∠B. x = 7
m∠B = 8(7) - 30 = 26 degrees
also m∠A = m∠B
∠A and ∠B form a linear pair. If m∠A=(2x+8)∘ and m∠B=(2x+8)∘, solve for m∠A and m∠B.
2x + 8 + 2x + 8 = 180
x = 41
m∠A = m∠B = 2(41) + 8 = 90 degrees