Wyatt and Kole's final project

mean,median,mode range

100

 find all 4,6,8,6

mean:((4+6+8+6)/4=24/4=6)

Median((6+6)/2=6

mode:6

rang:8-4=4

200

 find all 12,15,10,8,15,20

Mean: Sum = 12 + 15 + 10 + 8 + 15 + 20 = 80 Mean = (80 ÷ 6 ≈ 13.33)

Median: Ordered: 8, 10, 12, 15, 15, 20 Middle two: 12 and 15 Median = ( (12 + 15) ÷ 2 = 13.5 )

Mode: 15

Range: (20 − 8 = 12)

300

find all 3, 9, 12, 15, 9, 18, 21

Mean: Sum = 3 + 9 + 12 + 15 + 9 + 18 + 21 = 87 Mean = (87 ÷ 7 = 12.43)

Median: Ordered: 3, 9, 9, 12, 15, 18, 21 Middle value = 12

Mode: 9

Range: (21 − 3 = 18)

400

find all 22, 18, 25, 30, 18, 40, 35, 22

Mean: Sum = 22 + 18 + 25 + 30 + 18 + 40 + 35 + 22 = 210 Mean = (210 ÷ 8 = 26.25)

Median: Ordered: 18, 18, 22, 22, 25, 30, 35, 40 Middle two: 22 and 25 Median = ( (22 + 25) ÷ 2 = 23.5 )

Mode: 18 and 22 (bimodal)

Range: (40 − 18 = 22)

500

find all 45, 52, 60, 45, 70, 80, 52, 90, 100, 45

Mean: Sum = 45 + 52 + 60 + 45 + 70 + 80 + 52 + 90 + 100 + 45 = 639 Mean = (639 ÷ 10 = 63.9)

Median: Ordered: 45, 45, 45, 52, 52, 60, 70, 80, 90, 100 Middle two: 52 and 60 Median = ( (52 + 60) ÷ 2 = 56 )

Mode: 45

Range: (100 − 45 = 55)

writing inequalities

100

“A number (x) is greater than 7.”

Inequality: (x > 7)

200

You must be older than 13 to join a club. Let (a) = age.

Inequality: (a > 13)

300

“Three times a number (x) is greater than 24.”

Inequality: (3x > 24)

400

A number (x) is between 4 and 10, inclusive.”

Inequality: (4 \le x \le 10)

500

“A number (k) is no less than 3 but strictly less than 12."

Inequality: (3 \le k < 12)

solving equations

100

(x + 7 = 15)

Answer: (x = 8)

200

(3y = 27)

 Answer: (y = 9)

300

(5x - 4 = 21)  

Answer: Add

400

(5x = 25) Divide: (x = 5)4. ({m}{6} + 2 = 7) 

 Answer: Subtract 2: (\dfrac{m}{6} = 5) Multiply: (m = 30)

500

 (4(2x - 3) = 28) 

Answer: Distribute: (8x - 12 = 28) Add 12: (8x = 40) Divide: (x = 5)

solving inequalitie

100

(x + 6 < 14)

 Solution: Subtract 6: (x < 8)

200

(3y \ge 21)  

Solution: Divide by 3: (y \ge 7)

300

(5x - 10 \le 20)

 Solution: Add 10: (5x \le 30)

400

(m > 20) 5. (-2x + 4 \le 10) 

( Solution: Subtract 4: (-2x \le 6) Divide by –2 (flip inequality): (x \ge -3)

500

 (x \le 6) 4. (\dfrac{m}{4} + 3 > 8) 

 Solution: Subtract 3: (\dfrac{m}{4} > 5) 

Evaluating Expressions

100

Evaluate (3x + 5) when (x = 4).

.

Answer: (3(4) + 5 = 12 + 5 = 17)

200

2. Evaluate (2y^2) when (y = 3).

Answer: (2(3^2) = 2(9) = 18)

300

3. Evaluate (6 - a) when (a = 10).

Answer: (6 - 10 = -4)

400

4. Evaluate (\frac{m}{2} + 7) when (m = 8).

Answer: (4 + 7 = 11)

500

5. Evaluate (4n - 3n^2) when (n = 2).

Answer: (4(2) - 3(4) = 8 - 12 = -4)