Simple/Compound Interest
Growth and decay
Factorising
Solving equations
100

Sarah invests $1,000 at a simple interest rate of 5% per annum for 3 years. How much interest does she earn?

$150

100

A bacteria culture starts with 200 bacteria and doubles every hour. How many bacteria will there be after 3 hours?

1,600 bacteria

100

Factorise:   x2+5x+6

(x+2)(x+3)

100

Solve (x+5)(x+7)=0

x=-5   x=-7

200

Mark deposits $2,500 in a savings account that earns simple interest at a rate of 4% per annum. How much money will Mark have in his account after 5 years?

$3,000

200

A car depreciates in value by 10% each year. If the car is currently worth $20,000, what will it be worth after 1 year?

$18,000

200

Factorise: x2-7x+10

(x-2)(x-5)

200

Solve (x-17)(x+6)=0

x=17   x=-6

300

Emily invests $5,000 at an annual interest rate of 6% compounded annually. How much will her investment be worth after 2 years?

$5,618

300

How many kids does Mr Urkin have?


Bonus - What are their names?

Maya and Lily

300

Factorise: x2-9x+18

(x-3)(x-6)

300

Solve 5(x-5)(x+1)=0

x=5   x=-1

400

A bank offers an annual interest rate of 8% compounded monthly. If John invests $2,000, how much will he have after 2 years?  

$2,345.16

400

A substance decays by 25% each hour. If the initial amount is 80 grams, how much will be left after 2 hours?

45 grams

400

Factorise: 5x-15

5(x-3)

400

Solve x(x-9)=0

x=0   x=9

500

An amount of $1,500 is invested at an interest rate of 8% per annum, compounded monthly. Calculate the total amount after 2 years.

$1,757.55

500

A city's population is currently 50,000 and is growing at a rate of 3% per year. What will the population be in 5 years, assuming exponential growth?

Approximately 57,964

500

Factorise: 2x2+18x

2x(x+2)

500

Solve 5x(5-x)=0

x=0   x=5

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