10th PreCalc A

doMain Street

300

find the domain:

f(x)=x^2+xroot()(5)+|x|

{xeR}

400

find the domain:

f(x)=(x+2)/(x^2-6x+5)

{xeR |x<>1,5}

500

find the domain:

f(x)=root()(x+6)/(x-5)

{xeR |x>=-6,x<>5}

you call yourself a function?

300

function or not a function?

y=3x^3+2x^2+x+1

function

400

function or not a function?

y=+-root()(x-2)

not a function

500

function or not a function?

x^2+y^2=1

not a function

it's complicated

300

(12i^6+3i^5-2i^4)/(1-5i^2+3i^3)

-31/15-8/15i

400

if f(x) = x+3 and g(x)=x^2+1

evaluate f(g(x+1))

x^2+2x+5

500

(root(3)(a)root()(b)(root(4)(ab))^3)/(a^-2b^3(root()(a))^3b^-2

a^(19/12)b^(1/4)

final jeopardy

500

solve:

x^2+y^2=4

2x+y=1

((2+root()(19))/5,(1-2root()(19))/5),((2-root()(19))/5,(1+2root()(19))/5)