Determine the x intercepts algebraically
x+2y=7
3x-2y=-11
x+2y=7
3x-2y=-11
4x=4x
4x/4=-4/4
x=-1
-1+2y=7+1
2y=8
2x^{2}-5x-12=0
(-3/2,4)
(2x-1)(4x-3)=0
2x-1=0; 4x-3=0
2x-1=0 4x-3=0
2x=1 4x=3
x = 1/2
x = 3/4
3x-y=1
3x+2y=16
(2,5)
y=x^{2}-2x-3
y=x^{2}-2x-3
0=x^{2}-2x-3
0= (x+1)(x-3)
x=-1 x=3