reaction types
Thermochemistry
Calorimetry
Energy & Work
Mixed Chemistry
100

What type of reaction occurs when two or more substances combine to form one product?


What is a combination reaction?

100

A reaction that releases heat to the surroundings is called what?

What is an exothermic reaction?


100

What equation is commonly used to calculate heat transferred when you know mass, specific heat, and temperature change?

q = mcΔT


100

What is the difference between the system and the surroundings?


The system is what we are focusing on, while the surroundings are everything else that could be affected by a change in the system.

100

Is enthalpy (H) a state function or a path function?

State function

200

In a single-displacement reaction, a reaction occurs when the neutral metal is ______ on the activity series than the metal ion it is trying to replace

What is higher?

200

A reaction that absorbs heat from the surroundings is called what?

What is an endothermic reaction?


200

In a coffee-cup calorimeter, is the process generally considered to occur at constant pressure or constant volume?

Constant pressure

200

According to the First Law of Thermodynamics, can energy be created or destroyed?

 

no.

Energy can only be transferred as heat and/or work. 

200

When bonds are broken, is energy absorbed or released?

Energy is absorbed.


300

Determine whether a reaction occurs:

Zn(s) + Cu²⁺(aq) → ?

Given that Zn is above Cu on the activity series.

Yes, a reaction occurs.

300

A reaction has:

q = −450 J

Is the reaction exothermic or endothermic?

Exothermic

The negative q means the system released heat.

300

How much heat is required to heat 50.0 g of water from 20.0°C to 30.0°C?

Specific heat of water:

4.184 J/g°C

q = mcΔT

q = (50.0)(4.184)(30.0 − 20.0)

q = (50.0)(4.184)(10.0)

q = 2092 J = 2.092 kJ

300

A system absorbs 350 J of heat and does 200 J of work on the surroundings.

Calculate ΔE.

q = +350 J
w = −200 J

ΔE = 350 − 200

ΔE = +150 J


300

A reaction has:

q = −325 J

and

w = +125 J

Calculate ΔE.

ΔE = q + w

ΔE = −325 + 125

ΔE = −200 J

400

Which reaction type is represented?

2H₂O₂ → 2H₂O + O₂

Decomposition

400

A reaction absorbs 725 J of heat and does 125 J of work on the surroundings.


ΔE = q + w

q = +725 J
w = −125 J

ΔE = 725 + (−125)

ΔE = +600 J


400

A 100.0 g aluminum sample is heated from 25.0°C to 75.0°C.

The specific heat of Al is 0.900 J/g°C.

Calculate q.


q = mcΔT

q = (100.0)(0.900)(75.0 − 25.0)

q = (100.0)(0.900)(50.0)

q = 4500 J = 4.50 kJ


400

A gas expands from 2.0 L to 7.0 L against a constant external pressure of 1.0 atm.

Calculate the work.

Use: w = −PΔV and 1 L·atm = 101.325 J


ΔV = 7.0 − 2.0 = 5.0 L

w = −(1.0 atm)(5.0 L)

w = −5.0 L·atm

Convert:

−5.0 × 101.325 =

w ≈ −507 J

400

A 200.0 g copper sample is heated from 20.0°C to 80.0°C.

Copper's specific heat is 0.387 J/g°C.

How much heat is absorbed?

q = mcΔT

q = (200.0)(0.387)(80.0 − 20.0)

q = (200.0)(0.387)(60.0)

q = 4644 J = 4.64 kJ

500

Determine whether a reaction occurs:

Ni(s) + Na⁺(aq) → ?

Na is above Ni on the activity series.

No reaction

The Ni cannot displace Na⁺ because Ni is less reactive.

500

A system transfers 870 J of heat to the surroundings and does 420 J of work on the surroundings. Calculate E. 

q = −870 J
w = −420 J

ΔE = q + w

ΔE = −870 − 420

ΔE = −1290 J

500

A 75.0 g sample of water absorbs 2.50 kJ of heat. Its initial temperature is 22.0°C.

What is its final temperature?

Use:

c = 4.184 J/g°C


Convert:

2.50 kJ = 2500 J

2500 = (75.0)(4.184)(ΔT)

ΔT = 2500 / 313.8

ΔT = 7.97°C

Final temperature:

22.0 + 7.97 =

29.97°C ≈ 30.0°C

500

A system absorbs 1.20 kJ of heat while doing 0.850 kJ of work on the surroundings.

Calculate ΔE in Joules.


q = +1.20 kJ
w = −0.850 kJ

ΔE = q + w

ΔE = 1.20 − 0.850

ΔE = 0.350 kJ

ΔE = +350 J

500

A reaction releases 5.00 kJ of heat while the system has 1.25 kJ of work done on it by the surroundings.

What is ΔE?

Releases heat:

q = −5.00 kJ

Work done on the system:

w = +1.25 kJ

ΔE = q + w

ΔE = −5.00 + 1.25

ΔE = −3.75 kJ